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muminat
2 years ago
9

Active time 45:56 please help

Mathematics
2 answers:
exis [7]2 years ago
6 0

Answer:

\frac{\pi }{\sqrt[3]{27} }

Step-by-step explanation:

The third one

Any number with pi is irrational

MAXImum [283]2 years ago
6 0

Answer:

the third option \frac{\pi }{\sqrt[3]{27} }

Step-by-step explanation:

because pi cannot be put into a fraction

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Wire of length 20m is divided into two pieces and the pieces are bent into a square and a circle. How should this be done in ord
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Answer:

The radius of the circle ,r= 1.43 m

The length of the side of square ,a= 2.77 m

Step-by-step explanation:

Given that

L= 20  m

Lets take radius of the circle =r m

The total parameter of the circle = 2π r

Area of circle ,A=π r²

The side of the square = a m

The total parameter of the square = 4 a

Area of square ,A'=a²

The total length ,L= 2π r+ 4 a

20  = 2π r+ 4 a

r=3.18 - 0.63 a

The total area = A+ A'

                   A"   =π r² +a²

A"= 3.14(3.18 - 0.63 a)² + a²

For minimize the area

\dfrac{dA"}{da}=0

3.14 x 2(3.18 - 0.63 a) (-0.63) + 2 a = 0

3.14 x (3.18 - 0.63 a) (-0.63) + a = 0

-6.21 + 1.24 a + a=0

2.24 a = 6.21

a=2.77 m

r= 3.18 - 0.63 a

r= 3.18 - 0.63 x 2.77

r=1.43 m

Therefore the radius of the circle ,r= 1.43 m

The length of the side of square ,a= 2.77 m

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The HCF of 60 and 108 is 12. write their LCM
damaskus [11]

Answer:

What is the LCM of 60 and 108? The LCM of 60 and 108 is 540.

Step-by-step explanation:

What is the LCM of 60 and 108? The LCM of 60 and 108 is 540.

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If two angles have the same measure, then they are right angles true or false
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Step-by-step explanation:

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Rabies is a viral disease of mammals transmitted through the bite of a rabid animal. The virus infects the central nervous syste
lisabon 2012 [21]

Answer:

(a) The value of <em>x</em> is 0.30.

(b) The probability that a reported case of rabies is not a raccoon is 0.45.

(c) The probability that a reported case of rabies is either a bat or a fox is 0.15.

Step-by-step explanation:

Denote the events as follows:

<em>R</em> = reported case of rabies is a raccoon

<em>F</em> = reported case of rabies is a fox

<em>B</em> = reported case of rabies is a bat

<em>O</em> = reported case of rabies is a some other animal.

The data provided is:

P (R) = 0.55

P (F) = 0.11

P (B) = 0.04

P (O) = <em>x</em>.

(a)

A property of a probability distribution is that the sum of all individual properties is 1.

That is, \sum P(X)=1

Compute the value of <em>x</em> as follows:

\sum P(X)=1\\P(R)+P(F)+P(B)+P(O)=1\\0.55+0.11+0.04+x=1\\0.70+x=1\\x=1-0.70\\x=0.30

Thus, the value of <em>x</em> is 0.30.

(b)

The probability of the complement of an event is the probability of its not happening.

P(A^{c})=1-P(A)

Compute the probability that a reported case of rabies is not a raccoon as follows:

P(R^{c})=1-P(R)\\=1-0.55\\=0.45

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.

(c)

Compute the probability that a reported case of rabies is either a bat or a fox as follows:

P(B\cup F)=P(B)+P(F)\\=0.11+0.04\\=0.15

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.

4 0
3 years ago
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