I don't think that's possible.
Answer:
x = 3 , y = 1
Step-by-step explanation:
2x + y = 7
3x + y = 8
solution
2x + y = 7-----------(1)
3x - y = 8------------(2)
from equation 1
2x + y = 7
y = 7 - 2x-------------(3)
substitute equation 3 into equation 2
3x - y = 8
3x - (7 - 2x) = 8
3x - 7 + 2x = 8
3x + 2x = 8 + 7
5x = 15
divide through by the coefficient of x
5x/5 = 15/5
x = 3
to find y
substitute x into equation 1
2x + y = 7
2(3) + y = 7
6 + y = 7
y = 7 - 6
y = 1
Answer: The quadrilateral used here is a trapezium.
Answer:
Yes, 2x=4 is 2 simply by dividing, and 4x+5=13 is 2 as well, because 5-13 is 8 and 8 divided by 4 is 2
Answer:

Step-by-step explanation:
Given

Required
Integrate
We have:

Let

Differentiate

Make dx the subject

So, we have:



Express x^(10) as x^(5*2)

Rewrite as:

Recall that: 

Integrate

Substitute: 

Hence:
