Vertex=(-1,0)
x^2-2x-1
y=− ( x + 1 )^2 + 0
Use the vertex form, y=a(x−h)^2+k, to determine the values of a, h, and k.
Find the vertex (h,k) = (-1,0)
It looks like your instructor wants you to write in point-slope form.
the equation for point slope form is quite simple
y-y1=m(x-x1)
your variables:
y and x: just state these as they are
m: slope
y1 and x1: the numbers in the point given
keep in mind a double negative equals a positive, so when you come across a negative coordinate you would put + instead of - in your equation.
your final answer would be
y+2=-2(x-4)
I hope this helped :)
please don't hesitate to ask if you have any more questions
Answer:
y = 6x + 9
Step-by-step explanation:
The equation of a line in slope- interceot form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange 2x + 12y = - 1 into this form
Subtract 2x from both sides
12y = - 2x - 1 ( divide all terms by 12 )
y = - 
x - 
← in slope- intercept form
with slope m = -
Given a line with slope m then the slope of a line perpendicular to it is
= - 
= - 
= 6
Note the line passes through (0, 9) on the y- axis ⇒ c = 9
y = 6x + 9 ← equation of perpendicular line
Step-by-step explanation:
what the f♤ck are those. any teachers give u it tell them to go do it
