There are several ways the door can be locked, these ways illustrate combination.
There are 3375 possible combinations
From the question, we have:
--- the number of digits
---- the number of actions
Each of the three actions can either be:
- <em>Pressing one button</em>
- <em>Pressing a pair of buttons</em>
<em />
The number of ways of pressing a button is:

Apply combination formula




The number of ways of pressing a pair is:

Apply combination formula




So, the number of ways of performing one action is:



For the three actions, the number of ways is:



Hence, there are 3375 possible combinations
Read more about permutation and combination at:
brainly.com/question/4546043