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3 years ago

Which equation represents a line that passes through (–9, –3) and has a slope of –6?

1 answer:

8 0

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ -9}}\quad ,&{{ -3}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies -6
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-3)=-6[x-(-9)]
\\\\\\
y+3=-6(x+9)\implies y+3=-6x-54\implies y=-6x-57$

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According to records in a large hospital, the birth weights of newborns have a symmetric and bell-shaped relative frequency dist

Kamila [148]

Answer:

15.9% of babies are born with birth weight under 6.3 pounds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.8 pounds

Standard Deviation, σ = 0.5

We are given that the distribution of birth weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(birth weight under 6.3 pounds)

P(x < 6.3)

$P( x < 6.3) = P( z < \displaystyle\frac{6.3 - 6.8}{0.5}) = P(z < -1)$

Calculation the value from standard normal z table, we have,

$P(x < -1) = 0.159 = 15.9\%$

15.9% of babies are born with birth weight under 6.3 pounds.

8 0

2 years ago

Solve for z. Please show your work. 8z = 2z + 18

Nataly_w [17]

Answer:

x = 3

Step-by-step explanation:

8z = 2x + 18

6x = 18

x = 3

4 0

3 years ago

Read 2 more answers

What's the answer to 4+7(-10n-5)

strojnjashka [21]

What you would do is -10+5=-5 then you add 4+7= 11 then you mutiply them answers together 11*-5=-55 hope this helps you

8 0

3 years ago

The equation of a line is y = 2x − 6. Find the slope and y-intercept of the line.

SCORPION-xisa [38]

Answer:

Slope is 2 and y-int is -6

Step-by-step explanation:

y=mx+b

M is slope

B is y-int

7 0

2 years ago

Read 2 more answers

Solve the equation on the interval [0,2π). cos^4x=cos^4xcscx

Alisiya [41]

$\bf cos^4(x)=cos^4(x)csc(x)\\\\
-----------------------------\\\\
cos^4(x)=cos^4(x)\cfrac{1}{sin(x)}\implies cos^4(x)=\cfrac{cos^4(x)}{sin(x)}
\\\\\\
cos^4(x)sin(x)=cos^4(x)\implies cos^4(x)sin(x)-cos^4(x)=0
\\\\\\
cos^4(x)[sin(x)-1]=0\to 
\begin{cases}
cos^4(x)=0\to x=cos^{-1}(0)\\
----------\\
sin(x)-1=0\\
sin(x)=1\to x=sin^{-1}(1)
\end{cases}$

$\bf \measuredangle x = cos^{-1}(0)\implies \measuredangle x = 
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}
\\\\\\
\measuredangle x=sin^{-1}(1)\implies \measuredangle x=\frac{\pi }{2}$

3 0

3 years ago