Answer:
Remember if cosecθ=1/sinθ
sinθ×cosecθ=sinθ×1/sinθ=1
CMIIW
⅓x² +11x-75<105
⅓x² +11x-75-105<0
⅓x² +11x -180<0
x² +33x - 540<0
(x+45)(x-12)<0
(x-12)<0 or (x+45)>0
x<12 or x >-45
answer is A
The dimensions of the garden that will require the least amount of fencing are 450 m and 900 m and the perimeter of the area is 1800 m.
<h3>What is the area of the rectangle?</h3>
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
Let's suppose x and y are the sides of the rectangular garden and y is the parallel to the river.
Then according to the problem:
2x + y = P ..(1)
P is the perimeter of the rectangle.
xy = 405000 (area of the rectangle)
Plug the value of y in the equation (1) from the above equation.
P(x) = 2x + 405000/x
P'(x) = x—405000/x² = 0
x = 450 m
P''(x) > 0 hence at x = 450 the value of P(x) is minimum.
y = 405000/450
y = 900 m
P(min) = 1800 m
Thus, the dimensions of the garden that will require the least amount of fencing are 450 m and 900 m and the perimeter of the area is 1800 m.
Learn more about the rectangle here:
brainly.com/question/15019502
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Answer:
hey, there!
Step-by-step explanation:
The given is a point (-6,8) through which a line passes. And is perpendicular to the line y = 2x-4
The equation for point (-6,8) is,
(y-8)= m1(x+6)...........(i)
and given equation is y = 2x-4............(ii)
Now, from equation (ii).
slope (m2)= 2 { as equation (ii) is in the form of y= mx+c where m is a slope}.
Now, For perpendicular,
m1×m2= -1
m1×2= -1
Therefore, m1 = -1/2.
Putting, the value of m1 in equation (i).
(y-8) = -1/2×(x+6)
2(y-8)= -1(x+6)
2y - 16 = -x -6
x+2y-10 = 0......... is the required equation.
Hope it helps...
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