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2 years ago

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please pa answer po.Barby has a small plot in the garden she planted 2/5 of it to radidhes and 1/4 to carrots.What part of the p

lot did she use?

2 answers:

Arte-miy333 [17]2 years ago

6 0

Step-by-step explanation:

please mark me as brainlest

Gennadij [26K]2 years ago

5 0

hope it helps u :) ......

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3(4)<br> Solve 3(x-9)=21

Bas_tet [7]

Answer:

X=16

Step-by-step explanation:

Solve 3(x-9)=21 IF X = 16

16-9 = 7

3X7= 21

7 0

3 years ago

Read 2 more answers

Verify cot x sec^4x=cotx +2tanx +tan^3x

Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

Verifying from left, we have

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { \tan}^{2} x )^{2}$

Expand the perfect square in the right:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { 2\tan}^{2} x + { \tan}^{4} x)$

We expand to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + \cot(x){ 2\tan}^{2} x +\cot(x) { \tan}^{4} x$

We simplify to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{2} x}{{ \cos}^{2} x} +\frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{4} x}{{ \cos}^{4} x}$

Cancel common factors:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{{ \sin}x}{{ \cos}x} +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}$

This finally gives:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

3 0

3 years ago

Assume that y varies inversely as x. If y=6 when x=-4, find x when y= 12/5

yawa3891 [41]

This answer is : Y=2.4

3 0

2 years ago

A researcher conducted an experiment to investigate the effectiveness of a medicated lotion in treating a skin irritation. A gro

Helga [31]

Answer:

It can be concluded that the medicated lotion has an effect on treating skin irritations.

Step-by-step explanation:

In this case we need to determine whether the medicated lotion was effective in treating the skin irritation or not.

The hypothesis can be defined as follows:

<em>H₀</em>: There is no difference between the two proportions, i.e. <em>p</em>₁ - <em>p</em>₂ = 0.

<em>Hₐ</em>: There is a significant difference between the two proportions, i.e. <em>p</em>₁ - <em>p</em>₂ ≠ 0.

The information provided is:

n₁ = 40

n₂ = 40

X₁ = 36

X₂ = 16

Compute the sample proportions and total proportions as follows:

$\hat p_{1}=\frac{36}{40}=0.90\\\\\hat p_{2}=\frac{16}{40}=0.40\\\\\hat P=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{36+16}{40+40}=0.65$

Compute the test statistic value as follows:

$z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{\hat P(1-\hat P)[\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}=\frac{0.90-0.40}{\sqrt{0.65(1-0.65)[\frac{1}{40}+\frac{1}{40}]}}=4.69$

The test statistic value is 4.69.

The decision rule is:

The null hypothesis will be rejected if the <em>p</em>-value of the test is less than the significance level.

Compute the <em>p</em>-value as follows:

$p-value=2\times P(Z$

The <em>p</em>-value of the test is very small.

The null hypothesis will be rejected at any significance level.

Thus, there is a significant difference between the two proportions.

So, it can be concluded that the medicated lotion has an effect on treating skin irritations.

6 0

3 years ago

Solve the system.<br> 2x+y = 3<br> -2y = 14 - 6x

bezimeni [28]

Answer:

The solution is: (2, -1)

Step-by-step explanation:

First we rewrite the second system equation

$-2y = 14 - 6x$ → $6x-2y=14$

Now we have the following system of equations:

$2x+y = 3$

$6x-2y=14$

To solve the system multiply the first equation by -3 and add it to the second equation

$-6x+-3y = -9$

$6x-2y=14$

--------------------------------------

$0-5y=5$

$y=-1$

Now we substitute the value of y in the first equation and solve for x

$2x-1 = 3$

$2x= 4$

$x= 2$

The solution is: (2, -1)

5 0

3 years ago

Read 2 more answers