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2 years ago

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please pa answer po.Barby has a small plot in the garden she planted 2/5 of it to radidhes and 1/4 to carrots.What part of the p

lot did she use?

2 answers:

Arte-miy333 [17]2 years ago

6 0

Step-by-step explanation:

please mark me as brainlest

Gennadij [26K]2 years ago

5 0

hope it helps u :) ......

You might be interested in

Find the values of p and q such that 4x^2+12x=4(x+p)^2-q

-Dominant- [34]

Answer:

p = 1.5 and q = 9

Step-by-step explanation:

Expand the right side then compare the coefficients of like terms on both sides, that is

4(x + p)² - q ← expand (x + p)² using FOIL

= 4(x² + 2px + p²) - q ← distribute parenthesis

= 4x² + 8px + 4p² - q

Comparing coefficients of like terms on both sides

8p = 12 ( coefficients of x- terms ) ← divide both sides by 8

p = 1.5

4p² - q = 0 ( constant terms ), that is

4(1.5)² - q = 0

9 - q = 0 ( subtract 9 from both sides )

- q = - 9 ( multiply both sides by - 1 )

q = 9

7 0

3 years ago

Refer to the previous exercise. The researchers wanted a sufficiently large sample to be able to estimate the probability of pre

Maru [420]

Answer:

<em>The large sample n = 117.07</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the estimate error (M.E) = 0.08

The proportion (p) = 0.75

q =1-p = 1- 0.75 =0.25

Level of significance = 0.05

Z₀.₀₅ = 1.96≅ 2

<u><em>Step(ii):-</em></u>

The Marginal error is determined by

M.E = $\frac{Z_{0.05} \sqrt{p(1-p)} }{\sqrt{n} }$

$0.08 = \frac{2 X \sqrt{0.75(1-0.75)} }{\sqrt{n} }$

Cross multiplication , we get

$\sqrt{n} = \frac{2 X \sqrt{0.75(1-0.75)} }{0.08 }$

√n = $\frac{2 X0.4330}{0.08} = 10.825$

squaring on both sides , we get

n = 117.07

<u><em>Final answer:-</em></u>

<em>The large sample n = 117.07</em>

6 0

3 years ago

Please help me. This is due today

sattari [20]

Answer:

it answer is 3 because it is trigonometry

3 0

3 years ago

I have 4 factors three of my factors are 1 , 2 and 6 what is my fourth factor

laiz [17]

4 because 1 times 4 = 4

7 0

3 years ago

Lim. √2x -√3x-a/√x-√a<br>x approaches a

Ludmilka [50]

Answer: $\sqrt{2}a-\sqrt{3}a-2\sqrt{a}$

Step-by-step explanation:

$\lim _{x\to \:a}\left(\sqrt{2}x-\sqrt{3}x-\frac{a}{\sqrt{x}}-\sqrt{a}\right)$

$=\sqrt{2}a-\sqrt{3}a-\frac{a}{\sqrt{a}}-\sqrt{a}$

$=\sqrt{2}a-\sqrt{3}a-2\sqrt{a}$

3 0

3 years ago