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3 years ago

Someone please help me

Mathematics

1 answer:

Anettt [7]3 years ago

7 0

X^2-12x+36 is a quadratic of the form ax^2+bx+c

It will have factors (x+j)(x+k) where jk=ac=36 and j+k=b=-12.

So j and k must be -6 and -6 so the quadratic factored is:

(x-6)(x-6)

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The volume of the oblique cylinder is 5,588 mm

andriy [413]

Answer:

the answer is 14.7 mm

Step-by-step explanation:

i just guessed and i got it right the first try so..

8 0

4 years ago

Seven times a number gives the same result as subtracting 1441 from 2001 what is the number right an equation and solve

Dmitriy789 [7]

Answer: 80

Step-by-step explanation:

2001-1441=560

560/7=80

80 x7=560

5 0

3 years ago

The 3rd term of a geometric sequence is -1/3 and the 8th term is 81. what is the 11th term?

shepuryov [24]

Answer: $t_{11}=-2187$

Step-by-step explanation:

$t_{3}=-1/3$

That is :

$ar^{2} = -1/3$ ................. equation 1

Also

$t_{8}=81$

that is

$ar^{7}=81$ ................. equation 2

divide equation 2 by equation 1 , that is

$\frac{ar^{7}}{ar^{2}} = 81 / -1/3$

$r^{5}=$ $81$ x $-3/1$

$r^{5}= -243$

find the fifth root of both sides

$r = -3$

substitute $r = -3$ , into equation 1 to find a , that is

$a(-3^{2})= -1/3$

$9a = -1/3$

multiply through by 3

$27a = -1$

$a =- 1/27$

To find the 11th term , the formula for the 11th term is given as :

$t_{11}=ar^{10}$

$t_{11}= -1/27(-3^{10})$

$t_{11}=-2187$

6 0

4 years ago

What is the least natural number that is greater than the largest 4-?digit numbers

Stells [14]

50? 50 is greater than 40s

5 0

4 years ago

Solve 15 + a = 31 for a

pentagon [3]

Answer:

a = 16

Step-by-step explanation:

To solve your question all you have to do is subtract 15 on both sides so,

15 - 15 + a = 31 - 15

Which will give you,

15 - 15 = 0

31 - 15 = 16

So,

a = 16

Hope this helps!!

5 0

3 years ago

Read 2 more answers