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Masteriza [31]
3 years ago
10

10. There are 40 students at Oostburg College majoring in computer science. Computer science is not considered an engineering ma

jor.
Calculate an estimate of the number of computer science majors you think are in the marching band. Explain how you calculated your estimate.

Mathematics
1 answer:
Luden [163]3 years ago
3 0

Answer:

x= 0.1905*40 = 7.62 \approx 8

So then we would expect between 7 or 8 computer science majors are in the marching band.

Step-by-step explanation:

For this case we assume the two frequency chart attached on the figure.

For this case we are interested on this question "If a randomly selected student is not majoring in engineering. What is the  probability that this student is in the marching band? "

And in order to calculate this probability we need to look at the row "Not engineering Major" and we see that we have a total of 630 people and from these we are interested in who are in the marching band and as we can see 120 satisfy this condition, so then we can find the probability like this:

p = \frac{120}{630}=0.1905

Now since we expect 0.1905 or 19.05% of students are from computer science mejors that are in the marching band and we have a sample selected of 40 students, then the expected value would be:

x= 0.1905*40 = 7.62 \approx 8

So then we would expect between 7 or 8 computer science majors are in the marching band.

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fomenos

{(0, 1), (0, 5), (2, 6), (3, 3)} is not a function because zero is repeated in (0, 1),(0, 5)

While

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To decide whether a relation is a function or not, the first elements of each ordered pair (domain) are observed.  In order for a relation to be a function, there should be no repetition in first elements of each ordered pair.

In the given group of points:

{(0, 1), (0, 5), (2, 6), (3, 3)} is not a function because zero is repeated in (0, 1),(0, 5)

While

{(1, 4), (2, 7), (3, 1), (5, 7)} is a function because there is no repetition in domain i.e. first element of each ordered pair is unique.

Keywords: Domain, Range

Learn more about functions at:

  • brainly.com/question/2821386
  • brainly.com/question/2860697

#LearnwithBrainly

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