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ale4655 [162]
3 years ago
10

Is there an error in the work and is the answer extraneous? if so why?​

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
8 0

Answer:

x = 4

Step-by-step explanation:

log₃[1 + log₃(2ˣ - 7)] = 1

log₃[1 + log₃(2ˣ - 7)] = log₃(3)

1 + log₃(2ˣ - 7) = 3

log₃(2ˣ - 7) = 2

log₃(2ˣ - 7) = log₃(3)²

2ˣ - 7 = 9

2ˣ = 9 + 7

2ˣ = 16

2ˣ = 2⁴

x = 4

By putting x = 4 in the original equation,

log₃[1 + log₃(2⁴ - 7)] = 1

log₃[1 + log₃(16 - 7)] = 1

log₃[1 + log₃(9)] = 1

log₃[1 + log₃(3)²] = 1

log₃[1 + 2] = 1

log₃[3] = 1

1 = 1

Therefore, x = 4 is not the extraneous solution and there is no error in your answer.

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What are the solutions to the quadratic equation x^2-16=0
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Good evening.


This is a incomplete quadratic equation, because it does not have the term bx. Therefore, we can solve this faster with the following strategy:

\mathsf{x^2 - 16 = 0}

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Please help!! will give brainliest and 20points!!! SUPER EASY PROBLEM
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Answer:

C. 184 ft²

Step-by-Step Explanation:

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First, substitute the known value into the equation:

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