Answer:
336 squirrels
Step-by-step explanation:
-This is a Mark-Recapture method.
-The population is estimated using the formula:
![N=\frac{MC}{R}](https://tex.z-dn.net/?f=N%3D%5Cfrac%7BMC%7D%7BR%7D)
where:
- N-is the estimated population size.
- M-is the number of individuals tagged
- C- is the total number captured the second time(both tagged and untagged)
- R-is the total number of tagged individuals recaptured.
#We substitute our values as follows to estimate N:
![N=\frac{MC}{R}\\\\=\frac{114\times 97}{33}\\\\=335.0909\approx336](https://tex.z-dn.net/?f=N%3D%5Cfrac%7BMC%7D%7BR%7D%5C%5C%5C%5C%3D%5Cfrac%7B114%5Ctimes%2097%7D%7B33%7D%5C%5C%5C%5C%3D335.0909%5Capprox336)
Hence, there are approximately 336 squirrels in the conservation area.
*population is always rounded up to the next whole number.
The GCF of 44 and 121 is 11
:)
Answer:
x = 30
Step-by-step explanation:
![\frac{x}{6} +1=6\\\\\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}\\\frac{x}{6}+1-1=6-1\\\\Simplify\\\frac{x}{6}=5\\\\\mathrm{Multiply\:both\:sides\:by\:}6\\\frac{6x}{6}=5\times\:6\\\\Simplify\\x=30](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B6%7D%20%2B1%3D6%5C%5C%5C%5C%5Cmathrm%7BSubtract%5C%3A%7D1%5Cmathrm%7B%5C%3Afrom%5C%3Aboth%5C%3Asides%7D%5C%5C%5Cfrac%7Bx%7D%7B6%7D%2B1-1%3D6-1%5C%5C%5C%5CSimplify%5C%5C%5Cfrac%7Bx%7D%7B6%7D%3D5%5C%5C%5C%5C%5Cmathrm%7BMultiply%5C%3Aboth%5C%3Asides%5C%3Aby%5C%3A%7D6%5C%5C%5Cfrac%7B6x%7D%7B6%7D%3D5%5Ctimes%5C%3A6%5C%5C%5C%5CSimplify%5C%5Cx%3D30)
Answer:
1/16
Step-by-step explanation:
Given the expression;
![x^2+\dfrac{1}{2}x](https://tex.z-dn.net/?f=x%5E2%2B%5Cdfrac%7B1%7D%7B2%7Dx)
To find a constant that will make it a perfect square, we will use the square if the half of coefficient of x
Coefficient of x = 1/2
half of Coefficient of x = 1/2*(1/2)
Half of Coefficient of x = 1/4
square of the half of coefficient of x = (1/4)^2
square if the half of coefficient of x = 1/16
hence the constant that will make it a perfect square is 1/16