Answer:
<h3>Attachment</h3>
Step-by-step explanation:
Convert to the slope-intercept form (<em>y = mx + b</em>):
<em>divide both sides by 2</em>
We choose any three x values and calculate the y value:
for x = -1
for x = 1
for x = -3
Mark the points on the coordinate plane and draw a line through the given points.
Answer:
uhbsu is ysab nq17y 8
Step-by-step explanation:
Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
Answer:
32y^2-32
Step-by-step explanation:
4y^2+4(7y^2-8)
4y^2+28y^2-32
32y^2-32
if you need extra steeps explaining then plz let me know and I will help :)
Answer:229.1
Step-by-step explanation: to much work I thought to hard that’s the answer your welcome buddy
