Answer:
5/6
Step-by-step explanation:
1/2 + 1/3 need a common denominator to add them up.
1/2 is the same as 3/6.
1/3 is the sane as 2/6.
3/6 + 2/6
Add the tops, but keep the same denominator.
3/6 + 2/6 = 5/6
5/6 cannot be simplified, so that's the answer. That's how you do it! Hope this helps!
Answer:
![\large\boxed{D.\ 2x^2y\sqrt[5]{7xy^3}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BD.%5C%202x%5E2y%5Csqrt%5B5%5D%7B7xy%5E3%7D%7D)
Step-by-step explanation:
![\sqrt[5]{224x^{11}y^8}\\\\=\sqrt[5]{(32)(7)x^{5+5+1}y^{5+3}}\\\\\text{use}\ a^na^m=a^{n+m}\\\\=\sqrt[5]{(2^5)(7)x^5x^5x^1y^5y^3}\\\\\text{use}\ \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\=\sqrt[5]{2^5}\cdot\sqrt[5]{x^5}\cdot\sqrt[5]{x^5}\cdot\sqrt[5]{y^5}\cdot\sqrt[5]{7xy^3}\\\\\text{use}\ \sqrt[n]{a^n}=a\\\\=2\cdot x\cdot x\cdot y\cdot\sqrt[5]{7xy^3}\\\\=2x^2y\sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B224x%5E%7B11%7Dy%5E8%7D%5C%5C%5C%5C%3D%5Csqrt%5B5%5D%7B%2832%29%287%29x%5E%7B5%2B5%2B1%7Dy%5E%7B5%2B3%7D%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20a%5Ena%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C%5C%5C%3D%5Csqrt%5B5%5D%7B%282%5E5%29%287%29x%5E5x%5E5x%5E1y%5E5y%5E3%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20%5Csqrt%5Bn%5D%7Bab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%5Ccdot%5Csqrt%5Bn%5D%7Bb%7D%5C%5C%5C%5C%3D%5Csqrt%5B5%5D%7B2%5E5%7D%5Ccdot%5Csqrt%5B5%5D%7Bx%5E5%7D%5Ccdot%5Csqrt%5B5%5D%7Bx%5E5%7D%5Ccdot%5Csqrt%5B5%5D%7By%5E5%7D%5Ccdot%5Csqrt%5B5%5D%7B7xy%5E3%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%5C%5C%5C%5C%3D2%5Ccdot%20x%5Ccdot%20x%5Ccdot%20y%5Ccdot%5Csqrt%5B5%5D%7B7xy%5E3%7D%5C%5C%5C%5C%3D2x%5E2y%5Csqrt%5B5%5D%7B7xy%5E3%7D)
16x^2 is the <span>perfect square of 4x^2</span>
Answer:
Step-by-step explanation: um
7√27 + 5√48
7 × 3√3 + 5√48
7 × 3√3 + 5 × 4√3
21√3 + 5 × 4√3
21√3 + 20√3
41√3 or 71.014
hope this helps, God bless!
