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JulijaS [17]
3 years ago
13

What 10 times 913452

Mathematics
2 answers:
Oksana_A [137]3 years ago
7 0
10 times 913442 is 9134520.
klio [65]3 years ago
7 0
9,134,520 is the answer
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TQ is equal to or congruent to QR. Find m∠SQT.<br> A. 21<br> B. 10<br> C. 4 <br> D. 69
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D is the answer to this question.....
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The Oliver family ate 3/8 of a casserole
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Check the picture below.

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3 years ago
Solve for y
Andreas93 [3]

Answer:

y = 3

Step-by-step explanation:

2y - 3 = \sqrt{3y^2-10y+12}

square both sides to remove sqrt bracket

(2y - 3)^2 = ( \sqrt{3y^2-10y+12} )^2

simplify both sides

(2y - 3)(2y - 3) = 3y^2 - 10y + 12

4y^2 - 12y + 9 = 3y^2 - 10y + 12

bring all value to left side

y^2 - 2y - 3 = 0

factor

(y - 3)(y + 1)

solve for y

y = 3, y = -1

When plugged back into the equation, only y = 3 is true

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3 years ago
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Help help help math math
Contact [7]

\frac{2 |x - 3| }{5}  = 6 \\

5 \times  \frac{2 |x - 3| }{5}  = 5 \times 6 \\

2 |x - 3|  = 30

\frac{2 |x - 3| }{2}  =  \frac{30}{2}  \\

|x - 3|  = 15

x - 3 = 15

x - 3 + 3 = 15 + 3

x = 18

<h2>OR</h2>

x - 3 =  - 15

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4 0
2 years ago
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Earth is represented on a map of a portion of the solar system so that its surface is the circle with equation x2+y2+8x+2y−4883=
vodka [1.7K]

Answer:

The general form of the equation for the orbit of the satellite is x^{2}+y^{2}+8\cdot x+2\cdot y = 4939.16.

Step-by-step explanation:

From statement we have the general equation of the elliptic form of Earth. First we have to transform this formula to the standard form of the equation of the circle. That is:

1) x^{2}+y^{2}+8\cdot x +2\cdot y -4883=0 Given

2) (x^{2}+8\cdot x)+(y^{2}+2\cdot y) = 4883 Associative, commutative and modulative properties/Compatibility with addition/Existence of additive inverse.

3) (x^{2}+8\cdot x +16)+(y^{2}+2\cdot y+1)-17=4883 Associative, commutative and modulative properties/Compatibility with addition/Existence of additive inverse.

4) (x+4)^{2}+(y+1)^{2} = 4900 Square perfect trinomial/Result

According the result, the center of Earth is C(x,y) = (4, 1) and the square of the radius of Earth equals 4900. That is: r = 70

If satellite circles 0.4 unit above Earth, then the equation of the orbit of the satellite is:

(x+4)^{2}+(y+1)^{2}=70.4^{2}

(x+4)^{2}+(y+1)^{2} = 4956.16

Now we transform this into its general form:

1) (x+4)^{2}+(y+1)^{2} = 4956.16 Given

2) x^{2}+8\cdot x +16+y^{2}+2\cdot y+1 = 4956.16 Square perfect trinomial

3) x^{2}+y^{2}+8\cdot x+2\cdot y = 4939.16 Associative, commutative and modulative properties/Compatibility with addition/Existence of additive inverse/Result

The general form of the equation for the orbit of the satellite is x^{2}+y^{2}+8\cdot x+2\cdot y = 4939.16.

6 0
3 years ago
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