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2 years ago

What is the solution to the equation 2x+4 - 12 - 20? X=0 X=1 X=2 x=9

Mathematics

2 answers:

Andre45 [30]2 years ago

8 0

Answer:x= 1

Step-by-step explanation:

Nikitich [7]2 years ago

7 0

Answer:

x=1 is correct took the test on edg 2020!!!

Step-by-step explanation:

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Label the slope and y intercept

dedylja [7]

Y intercept is (0,3)
Slope is 3/2

6 0

3 years ago

How many times larger then 2x10² is 2x10⁸

Brrunno [24]

Answer:

1,000,000 times larger

Step-by-step explanation:

2 x $10^{8}$ = 200,000,000

2 x $10^{2}$ = 200

200,000,000 divided by 200 is 1,000,000

It can also be solved by subtracting the exponents from 10. Then dividing the two number being put the scientific notation.

$10^{8} - 10^{2}$ = $10^{6$

2 ÷ 2 = 1

Now solve:

1 x $10^{6$ = 1,000,000

3 0

2 years ago

R^4/9 translated verbal expression

Verizon [17]

Answer:

The quotient of 4 and 9 raised to the power of r.

Step-by-step explanation:

3 0

3 years ago

A rectangular prism has a length of 14 feet, a height of 11 feet, and a width of 13 feet. What is its volume, in cubic feet ?

Radda [10]

2002 ft^3. Hope this is right!

4 0

2 years ago

What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?

Trava [24]

Answer:

$\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}$

Step-by-step explanation:

The explicit formula for a geometric sequence:

$a_n=a_1r^{n-1}$

$a_n$ - n-th term

$a_1$ - first term

$r$ - common ratio

$r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}$

We have

$a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...$

The common ratio:

$r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}$

<h2>It's not a geometric sequence.</h2>

If $a_3=-\dfrac{1}{16}$ then the common ratio is $r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}$

Put to the explicit formula:

$a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}$

Put $a_n=\dfrac{1}{1024}$ and solve for <em>n </em>:

$-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1$

$\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6$

5 0

3 years ago