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3 years ago

Please help me solve this correctly. I need it ASAP!

Mathematics

1 answer:

Marina CMI [18]3 years ago

7 0

Answer:

A's

Step-by-step explanation:

Mode is defined as the number, or in this case grade, that appears most often in a set of numbers. Seeing as 10 is the most number of a certain grade recieved, the corresponding grade A is the mode.

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Contains the point (-1, 2) and is parallel to x – 2y = -3

ivanzaharov [21]

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange x - 2y = - 3 into this form

Subtract x from both sides

- 2y = - x - 3 ( divide all terms by - 2 )

y = $\frac{1}{2}$ x + $\frac{3}{2}$ ← in slope- intercept form

with m = $\frac{1}{2}$

• Parallel lines have equal slopes, thus

y = $\frac{1}{2}$ x + c ← is the partial equation

To find c substitute (- 1, 2) into the partial equation

2 = - $\frac{1}{2}$ + c ⇒ c = 2 + $\frac{1}{2}$ = $\frac{5}{2}$

y = $\frac{1}{2}$ x + $\frac{5}{2}$ ← in slope- intercept form

Multiply through by 2

2y = x + 5 ( subtract 2y from both sides )

0 = x - 2y + 5 ( subtract 5 from both sides )

- 5 = x - 2y, thus

x - 2y = - 5 ← in standard form

4 0

4 years ago

Find the percent of change. Round to the nearest percent.

katovenus [111]

Answer:

-54.5%

Step-by-step explanation:

You will have to use this formula

$\frac{new value-oldvalue}{oldvalue}$

When substituted in you have $\frac{30-66}{66}$

30-66=-36

-36/66= -0.54 (54 repeating)

Then you have to convert this into a percentage, -54.54(repeating) percent

To the nearest hundredth you would round down to -54.5%.

It is a Decrease because it is negatated.

8 0

3 years ago

I am a 2 digit number.

AlexFokin [52]

Answer:

Step-by-step explanation:

6+5=11

5 0

4 years ago

SOMEONE PLEASE HELP Choose the correct simplification of the expression (3xy2)4.

jek_recluse [69]

Answer is A or your first option.

8 0

4 years ago

Read 2 more answers

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago