3 years ago

Post assessment

Mathematics

1 answer:

lions [1.4K]3 years ago

3 0

1. D
2. E
3. B
4. Pentagon
5. C

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A) SSS B) SAS C) ASA D) AAS

Sav [38]

This is D.AAS (angle angle side)

4 0

3 years ago

Solve logs (8 - 3x) = log20 for x. A. X = 14 B. X = -13 C.x = -8 D. X= -4

Annette [7]

Answer:

x = -4

Step-by-step explanation:

logs (8 - 3x) = log20

Since we are taking the log on each side

log a = log b then a = b

8 -3x = 20

Subtract 8 from each side

8 -3x-8 =20 -8

-3x = 12

Divide by -3

-3x/-3 = 12/-3

x = -4

3 0

3 years ago

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4x+6y=60 y=2 solve for x

Zielflug [23.3K]

Answer:

x=12

Step-by-step explanation:

4x+6y=60 y=2

4x+6(2)=60

4x+12=60

4x=60-12

4x=48

x= $\frac{48}{4}$

x=12

5 0

3 years ago

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Evaluate: (x^2-1)/(x-1) if x goes to 1?

egoroff_w [7]

Step-by-step explanation:

$\displaystyle \lim_{x \to 1} \dfrac{(x^2 - 1)}{(x-1)} = \lim_{x \to 1} \dfrac{(x - 1)(x+1)}{(x-1)}$

$\:\:\:\:\:\:\:\:\displaystyle = \lim_{x \to 1} (x+1) =2$

6 0

3 years ago

7/9+6/8+6/3= please help me

Arada [10]

Hi ;-)

7/9 + 6/8 + 6/3 = 7/8 + 3/4 + 2 =

= 28/32 + 24/32 + 2 = 52/32 + 2 =

= 1 20/32 + 2 = 3 20/32 = 3 5/8

4 0

3 years ago

Read 2 more answers