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Answer:
28 ways
Step-by-step explanation:
After placing 1 ball in each of the seven bins, there are two balls left.
If we place both balls in a single bin, there are 7 different ways to place the balls (place both on bins 1 through 7).
If we place each of the remaining balls in a different bin, the number of ways to place the balls is:
The total number of ways to distribute those balls is 21 + 7 = 28 ways.
Remember
difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
and the undistributiv propeoryt
ab-ac=a(b-c)
so we have
undistribute and factor
cancel out the one ( (u-2)/(u-2)=1)
is result
difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
and the undistributiv propeoryt
ab-ac=a(b-c)
so we have
undistribute and factor
cancel out the one ( (u-2)/(u-2)=1)