Answer:
<h2>C.</h2>
Step-by-step explanation:
Look at the pictures.
x - sausage
y - bacon
A. 20 pounds of sausage and 90 pound of bacon
x = 20 → y = 100 > 90
B. 40 pound of sausage and 40 pound of bacon
x = 40 → y = 75 > 40
C. 60 pound of sausage and 80 pound of bacon
x = 60 → y = 50 < 80
D. 80 pound of sausage and 20 pound of bacon
x = 80 → y = 25 > 20
I think it's B. Because he spends his 300 dollars so he would have to subtract it will all the money he has spent.
The least number of boxes and bags needed are 3 and 2 respectively.
<u><em>Explanation</em></u>
Suppose, the number of boxes is
and the number of bags is ![y](https://tex.z-dn.net/?f=y)
Given that, pencils come in 8 in a box and erasers come 12 in a bag.
So, the total number of pencils in
number of boxes
and the total number of erasers in
number of bags ![=12y](https://tex.z-dn.net/?f=%3D12y)
As there are total 24 students and each student needs one pencil and one eraser to take a test, so...
![8x=24\\ \\ x= \frac{24}{8}=3](https://tex.z-dn.net/?f=8x%3D24%5C%5C%20%5C%5C%20x%3D%20%5Cfrac%7B24%7D%7B8%7D%3D3)
and
![12y=24\\ \\ y=\frac{24}{12}=2](https://tex.z-dn.net/?f=12y%3D24%5C%5C%20%5C%5C%20y%3D%5Cfrac%7B24%7D%7B12%7D%3D2)
So, the least number of boxes and bags needed are 3 and 2 respectively.