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grandymaker [24]
3 years ago
5

What are the coefficients of this equation? 5(2j + 3 + j)

Mathematics
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

2 and 1 because they are directly next to a variable

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4x−3y=8<br> 4x−y=−8<br> work out x and y
Alexeev081 [22]

Answer:

y = -8

x = -4

okay i hope you got it

6 0
3 years ago
Jules has 1200 and is spending 40 per week. kelsey has 400 and is saving 50 a week. in how many weeks, will jules and kelsey hav
expeople1 [14]
After x weeks:
Jules will have: 1,200 + 40 x.
Kelsey will have: 400 + 50 x.
If we want to know in how many weeks will they have the same amount of money, we will make an equation:
400 + 50 x = 1,200 + 40 x
50 x - 40 x = 1,200 - 400
10 x = 800
x = 800 : 10
x = 80
Answer: In 80 weeks they will have the same amount of money.
4 0
3 years ago
PLEASE HELP ME ASAP!!!!<br> The top says "Coffee cost $18.96 for 3 pounds."
mezya [45]
I think you divide 18.96 by 3 to get the amount for one pound cost then go pound for pound there
4 0
3 years ago
Read 2 more answers
Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is
Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since,  its head is twice as likely to occur as its tail.

p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n  = 3

p=\dfrac{2}{3}

q=\dfrac{1}{3}

Now,

P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0
3 years ago
Consider the following problem: a box with an open top is to be constructed from a square piece of cardboard, 3 feet wide, by cu
Alecsey [184]

Answer:

) See annex

b) See annex

x  =  0,5 ft

y =  2 ft   and

V = 2 ft³

Step-by-step explanation:  See annex

c) V = y*y*x

d-1) y = 3 - 2x

d-2) V = (3-2x)* ( 3-2x)* x   ⇒ V = (3-2x)²*x    

V(x) =( 9 + 4x² - 12x )*x    ⇒   V(x) = 9x + 4x³ - 12x²

Taking derivatives

V¨(x) = 9 + 12x² - 24x

V¨(x) = 0              ⇒   12x² -24x +9 = 0     ⇒  4x² - 8x + 3 = 0

Solving for x (second degree equation)

x =[ -b ± √b²- 4ac ] / 2a

we get    x₁  =  1,5       and    x₂ =  0,5

We look at y = 3 - 2x    and see that the value x₂ is the only valid root

then

x  =  0,5 ft

y =    2 ft   and

V = 0,5*2*2

V = 2 ft³

7 0
3 years ago
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