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topjm [15]
3 years ago
14

A box of oranges weighs 4 kg. If one orange weighs 80 g, how many oranges are in the box?

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0

Answer:

50 oranges

Step-by-step explanation:

Convert the measurements for them to be the same ie 4kg to g

1kg=1000g. 4kgx1000=4000g

4000g is the mass of all oranges

1 orange=80g

? =4000g that is 4000/80

=50 oranges

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alex41 [277]

Answer:

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i suck at explaining, but after the first step the expression looks like:

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Step-by-step explanation:

5 0
3 years ago
This is an isosceles trapezoid.<br> R.<br> s<br> 75<br> X<br> Y У<br> T<br> U
LekaFEV [45]

Answer:

S=R

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3 years ago
Read 2 more answers
Solve the equation -x/6greaterthanequalto3
enot [183]

Answer (depending if the fraction is positive or negative):

  1. x ≥ 18
  2. x ≤ -18

Step-by-step explanation:

If the fraction is positive:

  1. Write it out: \frac{x}{6} \geq 3  
  2. Multiply each side by 6 to cancel out the 6 under x. It should now look like this: x ≥ 18

If the fraction is negative:

  1. Write it out: -\frac{x}{6} \geq 3  
  2. Multiply each side by -6 to cancel out the -6 under x. It should now look like this: x ≤ -18

I hope this helps!

3 0
2 years ago
What is the equation of the circle with center (0, 0) that passes through the point (-8, 3)?
77julia77 [94]

 

hello :<span>
<span>an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = OP....p(-8,3)
r² = (OP)²
r² = (-8-0)² +(3-0)² = 64+9=73
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through P(-8, 3) is :  x² +y² = 73</span></span>

7 0
3 years ago
What is the area of the trapezoid
Zarrin [17]
I'm not sure because u don't have a pic of the trapezoid.
6 0
2 years ago
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