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topjm [15]
3 years ago
14

A box of oranges weighs 4 kg. If one orange weighs 80 g, how many oranges are in the box?

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0

Answer:

50 oranges

Step-by-step explanation:

Convert the measurements for them to be the same ie 4kg to g

1kg=1000g. 4kgx1000=4000g

4000g is the mass of all oranges

1 orange=80g

? =4000g that is 4000/80

=50 oranges

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3 3/5 + 6 3/10 please
Dafna11 [192]
In order to solve first convert both values into improper fractions:
18/5+63/10
second, convert both values to fractions with a base of ten:
36/10+63/10
finally, add the numerators:
99/10 is the final answer

3 0
3 years ago
Using traditional methods it takes 92 hours to receive an advanced flying license. A new training technique using Computer Aided
DanielleElmas [232]

Answer:

The value of the test statistic is z = 1.39.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

Step-by-step explanation:

Using traditional methods it takes 92 hours to receive an advanced flying license.

This means that at the null hypothesis, it is tested if the mean is of 92, that is:

H_0: \mu = 92

Test if there is evidence that the technique lengthens the training time

At the alternative hypothesis, it is tested if the mean is more than 92, that is:

H_1: \mu > 92

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

92 is tested at the null hypothesis:

This means that \mu = 92

A researcher used the technique on 70 students and observed that they had a mean of 93 hours. Assume the population variance is known to be 36.

This means that n = 70, X = 93, \sigma = \sqrt{36} = 6

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{93 - 92}{\frac{6}{\sqrt{70}}}

z = 1.39

The value of the test statistic is z = 1.39.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 93, which is 1 subtracted by the p-value of z = 1.39.

Looking at the z-table, z = 1.39 has a p-value of 0.9177.

1 - 0.9177 = 0.0823.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

8 0
2 years ago
Solve for x. (x - 4)(x - 4) = 0
statuscvo [17]
I believe that x=4 would be the answer
5 0
3 years ago
Read 2 more answers
24= g/g +20. g/g is a fraction.
Stells [14]

Answer:

Subtract 20 from both sides.

24−20=9/g

2 Simplify 24-20 to 4

4=9/g

3 Multiply both sides by 9

4×9=g

4 Simplify 4×9 to 36

36=g

5 Switch sides.

g=36

Step-by-step explanation:hope it helps plz Mark me brainliest

8 0
3 years ago
Students were surveyed about birthdays. How many more students were born on Wednesday than friday?
WINSTONCH [101]
1 more person ; 2-1 = 1
4 0
2 years ago
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