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andrezito [222]
3 years ago
8

Please help meee im being timed on thisss

Mathematics
1 answer:
sattari [20]3 years ago
4 0

Answer:

y=0.25x

We can think of k as an unknown number.

8×_=2.00

12×_=3.00

20×_=5.00

If we divide 2 with 8 we are left with 0.25.

It's the same for the other numbers so we know the constant is 0.25.

When we use the formula y=0.25x with the numbers above, it is correct.

8×0.25=2.00

12×0.25=3.00

20×0.25=5.00

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a rectangle that has a width of 2 inches and a length of 3 has been scaled by a factor of 7. what is the new width of the rectan
vichka [17]

Answer: 14 inches

Step-by-step explanation:

From the question, we are informed that a rectangle has a width of 2 inches and a length of 3 inches and has been scaled by a factor of 7.

This simply means that we've to multiply the width of the rectangle by 7 and also multiply the length of the rectangle by 7.

Old width = 2 inches

New width= 2 inches × 7 = 14 inches

The new width of the rectangle is 14 inches

4 0
2 years ago
In physics, it is important to use mathematical approximations. for instance, in a small angle approximation, tanα ∼ sin α . fin
siniylev [52]
Note that x is measured in radians.
The percent difference or error between sin(x) and tan(x) is calculated as 
d = 100( \frac{|sin(x)-tan(x)|}{sin(x)} )

We want this percent difference to be less than 10.4%.
Because tan(x) > sin(x) for small values of x, define
f(x) =  \frac{tan(x)-sin(x)}{sin(x)}= 0.104 \\ or \\ sec(x) - 1  = 0.104 \\ sec(x) = 1.104

From the calculator, obtain
sec⁻¹ 1.104 = 0.4375

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5 0
2 years ago
Y=x^2-2x what the vertex
____ [38]
I use my calculator
Y1 (the blue one) = x^2-2x
Graph
2nd trace minimum
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6 0
3 years ago
Refer previous problem. Suppose that you wish to estimate the difference between the mean acidity for rainfalls at two different
aivan3 [116]

Answer:

Hence,we need at least 136 rainfall PH values in the sample i.e

n ≥ 136

Step-by-step explanation:

We are given that:

(σ1)^2 = (σ2)^2 = Population variance = 0.25

So, E < 0.1

Confidence coefficient (c) = 0.9

n = n1 = n2

For confidence level, 1 - α = 0.9,we'll determine Z (α /2) = Z 0.05 by looking up 0.005 using the normal probability table which i have attached.

So, Z (α /2) = 1.645

The margin of error E is given as;

E = Z (α /2)√[(σ1)^2)/n1] + [(σ2)^2)/n2]

= Z (α /2)√({(σ1)^2 + (σ2)^2}/n) < 0.1

Multiply both sides by √n to get;

Z (α /2)√(σ1)^2 + (σ2)^2} < 0.1√n

Divide both sides by 0.1;

{Z (α /2)√(σ1)^2 + (σ2)^2}}/0.1 <√n

When we square each side, we get

{Z (α /2)√(σ1)^2 + (σ2)^2}}/0.1} ^2 < n

We'll now fill in the known values and solve;

n > ( 1.645 x √{(0.25 + 0.25)/0.1}^2

n > 135.3 or approximately n > 136

Hence,we need at least 136 observations in the sample i.e

n ≥ 136

7 0
3 years ago
a cirlcular patio has a diameter of 26ft. inside it is a round flower garden with a diameter of 6ft. to edge the patio and the g
Luden [163]

Answer: C just took the test

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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