Answer:
Step-by-step explanation:
h^2=x^2+y^2, since this is a square x=y=s so
220^2=2s^2
2s^2=48400
s^2=24200
s=24200^(1/2)m (exact)
s=155.56m (rounded to nearest hundredth of a meter)
One hectare is equal to 10000m^2
A=24200m^2(h/10000m^2)
A=2.42 hectares
Answer:
<em>Answer is</em><em> </em><em>given below</em><em> </em><em>.</em>
Step-by-step explanation:
Letters in the word "<em>MATHEMATICS</em><em> </em><em>"</em>
<em>M</em><em>,</em><em>A</em><em>,</em><em>T</em><em>,</em><em>H</em><em>,</em><em>E</em><em>,</em><em>I</em><em>,</em><em>C</em><em>,</em><em>S</em><em>.</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>
Answer:
226.08 yd 3
Step-by-step explanation:
Answer:
The common difference is same = d = -9
Therefore, the data represent a linear function.
Step-by-step explanation:
Given the table
x y
1 4
2 -5
3 -14
4 -23
5 -32
Finding the common difference between all the adjacent terms of y-values
d = -5 - 4 = -6,
d = -14 - (-5) = -14+5 = -9
d = -23 - (-14) = -23 + 14 = -9
d = -32 - (-23) = -32 + 23 = -9
It is clear that the common difference between all the adjacent terms is same.
Thus,
d = -9
We know that when y varies directly with x, the function is a linear function.
Here, it is clear that each x value varies 1 unit, and each y value varies -9 units.
i.e. The common difference is same = d = -9
Therefore, the data represent a linear function.
Answer:
27.5 minutes
Step-by-step explanation:
Using,
R/R' = 2ᵃ/ᵇ------------------ Equation 1
From the equation,
R = mass of Element X before radioactive decay, R' = mass of element X after radioactive decay, a = Time taken, b = half life.
Given: R = 870 grams, R' = 154 grams, b = 11 minutes.
Substitute these values into equation 1
870/154 = 2ᵃ/¹¹
(870/154)¹¹ = 2ᵃ
Solve for a
2ᵃ = (5.649)¹¹
2ᵃ = 187061.26
Taking the logarithm of both side,
Log2ᵃ = Log(187061.26)
⇒ a = log(187061.26)/log2
a = 8.272/0.301
a = 27.5 minutes