Answer:
<u>Part A: </u>
<u>n = 5q (1st equation)</u>
<u>0.05n + 0.25q = 2 (2nd equation)</u>
<u>Part B:</u>
<u>q = 4 ⇒ n = 5 * 4 = 20</u>
<u>Part C:</u>
<u>Margie has 20 nickels and 4 quarters, for a total of $ 2.00</u>
Step-by-step explanation:
Let's recall that a nickel has a value of $ 0.05 and a quarter a value of $ 0.25.
Let n represent the number of nickels and q represent the number of quarters.
Part A:
Write a system of equations to represent the situation.
n = 5q (1st equation)
n * 0.05 + q * 0.25 = 2
0.05n + 0.25q = 2 (2nd equation)
Part B:
Replacing n in the 2nd equation to solve for q:
0.05n + 0.25q = 2
0.05 * 5q + 0.25q = 2
0.25q + 0.25q = 2
0.5q = 2
q = 2/0.5
<u>q = 4 ⇒ n = 5 * 4 = 20</u>
<u>Part C:</u>
<u>Margie has 20 nickels and 4 quarters, for a total of $ 2.00</u>
Isolate "x" on one side of the algebraic equation by dividing the number that appears on the same side of the equation as part of "x."
Answer:
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Step-by-step explanation:
OK. I used my calculator to evaluate sec(85 degrees).
My calculator doesn't have a "sec" button on it.
But I remembered that
sec of an angle = 1 / (cosine of the same angle) .
So I used my calculator to find cos(85), and then I hit the
" 1/x " key, and got 11.474, which I knew to be sec(85).
Answer:

Explanation:
The <em>end behavior</em> of a <em>rational function</em> is the limit of the function as x approaches negative infinity and infinity.
Note that the the values of even functions are the same for ± x. That implies that their limits for ± ∞ are equal.
The limits of the quadratic function of general form
as x approaches negative infinity or infinity, when
is positive, are infinity.
That is because as the absolute value of x gets bigger y becomes bigger too.
In mathematical symbols, that is:

Hence, the graphs of any quadratic function with positive coefficient of the quadratic term will have the same end behavior as the graph of y = 3x².
Two examples are:
