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lana [24]
3 years ago
9

Please help me with this I’ll give 20 points and also brainlest for whoever gave me an accurate answer and thank you!

Mathematics
2 answers:
Leno4ka [110]3 years ago
4 0

do you have to show your work. if not then the answer is c


klemol [59]3 years ago
3 0

THIS ANSWER IS B TO THE ANSWER


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What is the solution to the equation below?<br><br>√2x/√x-1=2 <br><br>A. 4 B. 2 C. 5 D.3 <br>​
nikdorinn [45]

Given:

The given equation is:

\dfrac{\sqrt{2x}}{\sqrt{x-1}}=2

To find:

The solution for the given equation.

Solution:

We have,

\dfrac{\sqrt{2x}}{\sqrt{x-1}}=2

On simplification, we get

\sqrt{2x}=2\sqrt{x-1}

Squaring both sides, we get

2x=4(x-1)

2x=4x-4

2x-4x=-4

-2x=-4

Divide both sides by -2.

x=\dfrac{-4}{-2}

x=2

Therefore, the correct option is B.

6 0
3 years ago
Draw a diagram in which segment AB intersects segment CD equals segment CB
Contact [7]
The <u>correct diagram</u> is attached.

Explanation:

Using technology (such as Geogebra), first construct a line segment.  Name the endpoints C and D.

Construct the perpendicular bisector of this segment.  Label the intersection point with CD as B, and create another point A above it.

Measure the distance from C to B and from B to D.  They will be the same.

Measure the distance from A to B.  If it is not the same as that from C to B, slide A along line AB until the distance is the same.

Using a compass and straightedge:

First construct segment CD, being sure to label the endpoints.

Set your compass a little more than halfway from C to D.  With your compass set on C, draw an arc above segment CD.

With your compass set on D (the same distance as before) draw an arc above segment CD to intersect your first arc.  Mark this intersection point as E.

Connect E to CD using a straightedge; mark the intersection point as B.

Set your compass the distance from C to B.  With your compass on B, mark an arc on EB.  Mark this intersection point as A.

AB will be the same distance as CB and BD.

5 0
3 years ago
Read 2 more answers
In how many ways can a family of four be seated at a round table if two brothers must sit together?
Masteriza [31]
The 4-member family can be seated in 4! ways.
The two brothers can be seated together in 2! ways.

Therefore, the total number of ways is
\frac{4!}{2!} = \frac{4.3.2.1}{2.1} =4*3=12

Diagrammatically, the result is shown in the figure below. The two brothers are family members 3 and 4, shown in shaded color.

Answer: 12 ways.

6 0
3 years ago
A triangle has two sides of length 13 and 15. What is the largest possible whole-number length for the third side?
Brilliant_brown [7]

Answer:

27

Step-by-step explanation:

The third side must be shorter than the other 2 sides added together.

13 + 15 = 28, so at most it can be 27 , since it needs a whole number

7 0
3 years ago
HEEEEEEEEEEEEEEEEEEEEELP!!!! A line y=mx+b passes through point (16, −10) and is parallel to y=−34x+8.
ycow [4]

Answer:

b=2

Step-by-step explanation:

We know that the line passes through the point (16, -10).

And we also know that it is parallel to y=-\frac{3}{4}x+8

Notice that the slope of this line is -3/4

Remember that parallel lines have the same slope.

Therefore, the slope of our new line is also -3/4

Now, we can use the point-slope form:

y-y_1=m(x-x_1)

Where <em>m</em> is the slope and (x₁, y₁) is a point.

So, let’s substitute -3/4 for <em>m</em> and (16, -10) for (x₁, y₁). This yields:

y-(-10)=-\frac{3}{4}(x-16)

Distribute:

y-(-10)=-\frac{3}{4}x+12

Simplify:

y+10=-\frac{3}{4}x+12

Subtract 10 from both sides:

y=-\frac{3}{4}x+2

This is in the form <em>y=mx+b</em>.

Therefore, our <em>b</em> is 2.

And our final answer is 2.

5 0
3 years ago
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