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NARA [144]
3 years ago
11

How many real sixth roots are in 15,625?

Mathematics
1 answer:
Murljashka [212]3 years ago
3 0

There are two real roots  (5 and -5) and 4 imaginary roots

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Charlene puts together two isosceles triangles so that they share a base, creating a kite. The legs of the triangles are 10 inch
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From the information given you have:

1) Smaller diagonal of the kite: 16 inches


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3) Calculation of the height of the smaller triangle, h1:


10^2 = (16/2)^2 + (h1)^2 => h1 = √ [10^2 - 8^2] = 6


4) Calculation of the height of the larger triangle, h2


17^2 = (16/2)^2 + (h2)^2 => h2 = √[17^2  - 8^2] = 15


5) Larger diagonal = h1 + h2 = 6 + 15 = 21


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