Answer:
See below.
Step-by-step explanation:
A year has 12 months and 365 days.
3 months: 3/12 year = 1/4 year
55 days: 55/365 year = 11/73 year
1 month: 1/12 year
7 months = 7/12 year
120 days = 120/365 year = 24/73 year
x is the independent variable.
y is the dependent variable.
-3 is the rate of change (slope).
-7 is the initial value.
Step-by-step explanation:
The form of the linear relation is y = m x + b, where
- m is the rate of change (slope)
- b is the initial value(value of y at x = 0)
- x is the independent variable
- y is the dependent variable
∵ The equation of the line is y = -3 x - 7
- Compare it with the form above
∴ m = -3
∵ m is the rate of change
∴ The rate of change is -3
∴ b = -7
∵ b is the initial value
∴ The initial value is -7
∵ y depends on x
∴ x is the independent variable
∴ y is the dependent variable
x is the independent variable.
y is the dependent variable.
-3 is the rate of change (slope)
-7 is the initial value.
Learn more:
You can learn more about the linear equations in brainly.com/question/4152194
#LearnwithBrainly
For a given function, slope is defined as the change in outputs, or y-values divided by the change in inputs, or x-values. In essence the slope asks "For a given change in x, how much does y change?" or even more simply: "How steep is the graph of this function?". This can be represented mathematically by the formula:

Since we have a table of x,y pairs it's the last form of that equation that will be the most useful to us. To compute the slope we can use any two pairs, say the first two, and plug them into our formula:

We can check this answer by using a different pair, say the last two:

.
As a common sense check: Our y-values get smaller as our x-values get bigger so a negative slope makes sense.
m=-3
Answer:
I have never heard of it sorry
Answer:
The half-life of the radioactive substance is 135.9 hours.
Step-by-step explanation:
The rate of decay is proportional to the amount of the substance present at time t
This means that the amount of the substance can be modeled by the following differential equation:

Which has the following solution:

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.
After 6 hours the mass had decreased by 3%.
This means that
. We use this to find r.







So

Determine the half-life of the radioactive substance.
This is t for which Q(t) = 0.5Q(0). So







The half-life of the radioactive substance is 135.9 hours.