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Dominik [7]
2 years ago
8

Ahmad is choosing a password to access his teacher’s web page. He must choose a capital letter and three nonrepeating digits fro

m 0 through 9. The letter can be in any position in the password. Which shows part of the sample space for Ahmad’s password?
A135, 135A, 1A35, 13A5
A113, A123, A133, A143
0A23, 0a23,02A3, 02a3
1234, 5678, 0246, 1357
Mathematics
2 answers:
posledela2 years ago
8 0

Answer:

0a23,02A3 c

Step-by-step explanation:

please mark brainless

algol [13]2 years ago
7 0

Answer:

0a23,02A3

Step-by-step explanation:

I think that this is the right answer Im sorry if it is wrong

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<h2>Answer and Explanation to questions 13,14,15</h2>

13) \mathbf{\overline{XY}\cong\overline{CD}}        as given in the question.

14) \mathbf{\overline{XY}\cong\overline{YZ}}          Since Y is the midpoint of XZ. So, Y will divide XZ in equal halves into XY and YZ.

15) \mathbf{\overline{CD}\cong\overline{YZ}}

\because\overline{\textrm{XY}}\cong\overline{\textrm{CD}} and \overline{\textrm{XY}}\cong\overline{\textrm{YZ}} . So, \overline{\textrm{CD}}\cong\overline{\textrm{YZ}}

<h2>Answer and Explanation to questions 16,17,18</h2>

∠3 is supplementary to ∠1 means: ∠3 + ∠1 = 180°

And, according to figure ∠1 + ∠2 = 180° as ∠1 and ∠2 form a straight line.

∠3 + ∠1 = 180°    .............(i)

∠1 + ∠2 = 180°    .............(ii)

subtracting equation (i) and (ii) will give ∠3 = ∠2   ..........(iii)

15) ∠3 is supplementary to ∠1                        as given in the question

16) ∠2 is supplementary to ∠1                        as shown be equation (ii)

18) ∠3 ≅ ∠2                                                      as shown by equation (iii)

<h2>Answer and Explanation to questions 19</h2>

∠3 and ∠4 form a straight line. Therefore, ∠3 + ∠4 = 180°   .......(i)

∠4 and ∠5 form a straight line. Therefore, ∠4 + ∠5 = 180°   .......(ii)

subtracting equation (i) and (ii)

∠3 + ∠4 - (∠4 + ∠5) = 180°-(180°)

∠3 + ∠4 - ∠4 - ∠5 = 180°-180°

∠3 - ∠5 = 0

∴ ∠3 = ∠5     (Hence Proved)

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