Number of dimes collected is 339 and number of nickels collected is 113
<em><u>Solution:</u></em>
Given that There is a total of $39.55
There are 3 times as many dimes as nickels
To find: Number of dimes and nickels collected
Let "d" be the number of dimes collected
Let "n" be the number of nickels collected
We know that,
1 dime = $ 0.10
1 nickel = $ 0.05
From given information,
There are 3 times as many dimes as nickels
So, we get
Number of dimes = 3(number of nickels)
d = 3n
Given that there is total of $ 39.55
number of dimes collected x value of 1 dime + number of nickels collected x value of 1 nickel = $ 39.55
![3n \times 0.10 + n \times 0.05 = 39.55\\\\0.3n + 0.05n = 39.55\\\\0.35n = 39.55\\\\n = \frac{39.55}{0.35}\\\\n = 113](https://tex.z-dn.net/?f=3n%20%5Ctimes%200.10%20%2B%20n%20%5Ctimes%200.05%20%3D%2039.55%5C%5C%5C%5C0.3n%20%2B%200.05n%20%3D%2039.55%5C%5C%5C%5C0.35n%20%3D%2039.55%5C%5C%5C%5Cn%20%3D%20%5Cfrac%7B39.55%7D%7B0.35%7D%5C%5C%5C%5Cn%20%3D%20113)
Substitute n = 113 in d = 3n
![d = 3(113) = 339](https://tex.z-dn.net/?f=d%20%3D%203%28113%29%20%3D%20339)
<em><u>Summarizing the results:</u></em>
number of dimes collected = 339
number of nickels collected = 113