Answer:
The expected monetary value of a single roll is $1.17.
Step-by-step explanation:
The sample space of rolling a die is:
S = {1, 2, 3, 4, 5 and 6}
The probability of rolling any of the six numbers is same, i.e.
P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = 
The expected pay for rolling the numbers are as follows:
E (X = 1) = $3
E (X = 2) = $0
E (X = 3) = $0
E (X = 4) = $0
E (X = 5) = $0
E (X = 6) = $4
The expected value of an experiment is:

Compute the expected monetary value of a single roll as follows:
![E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17](https://tex.z-dn.net/?f=E%28X%29%3D%5Csum%20x%5Ccdot%20P%28X%3Dx%29%5C%5C%3D%5BE%28X%3D1%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5BE%28X%3D2%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5BE%28X%3D3%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%5C%5C%2B%5BE%28X%3D4%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5BE%28X%3D5%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5BE%28X%3D6%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%5C%5C%3D%5B3%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5B0%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5B0%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%5C%5C%2B%5B0%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5B0%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5B4%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%5C%5C%3D1.17)
Thus, the expected monetary value of a single roll is $1.17.
Answer: what are the options?
Step-by-step explanation:
You need to convert 3 lb, 6 oz into all ounces. To do this, know that 16 ounces is 1 pound.
(3pounds)(16 oz/1 pound)
This cancels out the pounds, and leaves you with 48ounces, then add the 6 ounces you already knew of. You now have 54 ounces, which is "D"
Answer:
0.042
Step-by-step explanation:
Given :
p = 16% = 0.16
q = 1 - p = 1 - 0.16 = 0.84
Sample size, n = 75
The standard deviation of sampling distribution :
√(pq)/n
√(0.16 * 0.84) / 75
√0.1344 / 75
√0.001792
Standard deviation of sampling distribution = 0.0423320