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pickupchik [31]
3 years ago
7

Toby goes on holiday to Geneva, Switzerland.

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
8 0

Answer:

Firstly, we have to transform CHF to \£ in order to work with the same currency and make the comparisson:

If \£1=1.55CHF

193.75CHF\frac{\£1}{1.55CHF}

Then:

193.75CHF=\£125

Now we can make the comparisons:

a) In Geneva the watch costs 193.75 CHF=\£125 and in Manchester it costs \£143.

According to this:

<h2>In Geneva the watch is cheaper</h2>

b) If we want to know by how much is cheaper, we have to substract from the expensive price the value of the cheaper price:

\£143-\£125=\£18

Therefore:

<h2>The watch in Geneva is \£18 cheaper than the same watch in Manchester.</h2>

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_ * 5 > 5

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Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

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\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

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How do you increase 429 Grams by 31%
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If you want to increase something by 31% then...

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you multiply it by 131% or 1.31. So for 429 grams...

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If you increase 429 by 31%, you get 561.99 grams

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Answer:

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Step-by-step explanation:

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