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pickupchik [31]
3 years ago
7

Toby goes on holiday to Geneva, Switzerland.

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
8 0

Answer:

Firstly, we have to transform CHF to \£ in order to work with the same currency and make the comparisson:

If \£1=1.55CHF

193.75CHF\frac{\£1}{1.55CHF}

Then:

193.75CHF=\£125

Now we can make the comparisons:

a) In Geneva the watch costs 193.75 CHF=\£125 and in Manchester it costs \£143.

According to this:

<h2>In Geneva the watch is cheaper</h2>

b) If we want to know by how much is cheaper, we have to substract from the expensive price the value of the cheaper price:

\£143-\£125=\£18

Therefore:

<h2>The watch in Geneva is \£18 cheaper than the same watch in Manchester.</h2>

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The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
zaharov [31]

Answer:

P(61≤ X≤94) = 49.85%

Step-by-step explanation:

From the given information:

The mean of the bell shaped fluorescent light bulb μ = 61

The standard deviation σ = 11

The objective of this question is to determine the approximate percentage of light bulb replacement requests numbering between 61 and 94 i.e P(61≤ X≤94)

Using the empirical (68-95-99.7)rule ;

At 68% , the data lies between  μ - σ and μ + σ

i.e

61 - 11 and 61 + 11

50 and 72

At  95%, the data lies between  μ - 2σ and μ + 2σ

i.e

61 - 2(11) and 61 + 2(11)

61 - 22 and 61 +22

39   and   83

At 99.7%, the data lies between  μ - 3σ and μ + 3σ

i.e

61 - 3(11) and 61 + 3(11)

61 - 33 and 61 + 33

28   and   94

the probability equivalent to 94 is when  P(28≤ X≤94) =99.7%

This implies that ,

P(28≤ X≤94) + P(61≤ X≤94) = 99.7%

P(28≤ X≤94) = P(61≤ X≤94) = 99.7 %    

This is so because the distribution is symmetric about the mean

P(61≤ X≤94) = 99.7 %/2

P(61≤ X≤94) = 49.85%

5 0
3 years ago
Segment LM is the mid segment of Trapezoid ABCD.AB=×+8,LM=4×+3,andDC=215.what is the value of x
tatyana61 [14]

Answer:

3.46

Step-by-step explanation:

add

8 0
4 years ago
www.g The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulb
damaskus [11]

Answer:

z=\frac{24-40}{8}=-2

z=\frac{40-40}{8}=0

And then the percentage between 24 and 40 would be \frac{95}{2}= 47.5 \%

Step-by-step explanation:

For this problem we have the following parameters given:

\mu = 40, \sigma =8

And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.

From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.

We can find the number of deviations from themean for the limits with the z score formula we got:

z=\frac{X-\mu}{\sigma}

And replacing we got:

z=\frac{24-40}{8}=-2

z=\frac{40-40}{8}=0

And then the percentage between 24 and 40 would be \frac{95}{2}= 47.5 \%

5 0
3 years ago
If you have $20 on your debit card can you buy a volleyball
Angelina_Jolie [31]
Yes. depending on where you buy it and how much the ball costs
5 0
3 years ago
in your stuffed animal collection you have 12 dogs, 10 more cats than dogs and 8 fewer bunnies than dogs
Alex787 [66]
22 cats, 4 bunnies, 12 dogs
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