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3 years ago

PLEASE HELP IM BEHIND AND SCHOOL IS OUT IN 2 DAYS

Mathematics

1 answer:

Alexxx [7]3 years ago

5 0

Answer: #1 his school is out

Step-by-step explanation: #2 bcuz all sides equal to 66cm.

Please mark me brainlest.✌✌

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deposits \$700 into an account that pays simple interest at a rate of 6\% per year. How much interest will he be paid in the fir

Virty [35]

Answer:

$210

Step-by-step explanation:

pnr/100

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3 years ago

X/3 - 13= 9 <br> Plz help its very confusing

Tpy6a [65]

Answer:

x = 66

Step-by-step explanation:

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3 years ago

Read 2 more answers

United Flight 15 from New York's JFK airport to San Francisco uses a Boeing 757-200 with 182 seats. Because some people with res

Tcecarenko [31]

Answer:

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

Step-by-step explanation:

For each passenger, there are only two outcomes possible. Either they show up for the flight, or they do not show up. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A probability is said to be unusually low if it is lower than 5%.

For this problem, we have that:

There are 200 reservations, so $n = 200$ .

A passenger consists in a passenger not showing up. There is a .0995 probability that a passenger with a reservation will not show up for the flight. So $\pi = 0.0995$ .

Find the probability that when 200 reservations are accepted for United Flight 15, there are more passengers showing up than there are seats available.

X is the number of passengers that do not show up. It needs to be at least 18 for the flight not being overbooked. So we want to find $P(X < 18)$ , with $\pi = 0.0995, n = 200$ . We can use a binomial probability calculator, and we find that:

$P(X < 18) = 0.2927$ .

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

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3 years ago

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Evgen [1.6K]

Answer:

Step-by-step explanation:

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3 years ago

From her window, Carmella looks up to the top of a neighboring building at an angle of 46°. Her

Vinil7 [7]

Answer:

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