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valentinak56 [21]
1 year ago
13

In a survey of 3400 people asked about their ice cream preference, 1600 enjoyed chocolate, 1250 enjoyedvanilla, 1700 enjoyed min

t, 700 enjoyed mint and chocolate, 500 enjoyed mint and a vanilla, 600 had achocolate and vanilla, and 200 enjoyed mint, chocolate, and vanilla.a. How many people enjoyed vanilla, but not chocolate or mint? b.How many people did not enjoy chocolate, vanilla, or mint?
Mathematics
1 answer:
velikii [3]1 year ago
4 0

Answer:

Step-by-step explanation:

To understand the situations we must do a Venn diagram:

The total of people asked is 3400. Then,

a) For People who enjoyed vanilla but not chocolate or mint, seeing the diagram of Venn, we can deduce the equations:

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b) For people who did not enjoy chocolate, vanilla or mint:

undefined

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ra1l [238]

Answer:4x14

Step-by-step explanation:

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In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
HELP NEEDED!!
Juli2301 [7.4K]
What answer did u get to this problem
5 0
3 years ago
Read 2 more answers
HELPPPPPPPPPPPPPPPPPPP
Anna11 [10]

Answer:

<em>5 ; 27 points</em>

Step-by-step explanation:

6x - 3 = x + 12

5x = 15

<em>x = 5</em>

GF = 6(5) - 3 = <em>27 units </em>

3 0
2 years ago
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