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Sever21 [200]
3 years ago
15

when a number in scientific notation contains a significant zero, is that zero also significant in the expanded notation? give t

wo examples to support your answer. PLEASE HELP I NEED ANSWERS ASAP
Chemistry
1 answer:
AlexFokin [52]3 years ago
4 0
I believe you are referring zero as the exponent. <span>Any number (except 0) with exponent 0 is defined to mean 1.
</span>

For one thing, there is a rule: 

<span> a^m/ a^m = a^m-m = a^0

</span>But (when a is not equal to <span>0),
</span>
a^m/ a^m = 1

Therefore, we must define a^0 as 1.

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If a solution has a pH of 2, what is the hydroxide ion concentration?
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Answer:

A

Explanation:

14=pH + pOH

pOH= 14 - 2

pOH= 12

pOH= -log[OH]

[OH]= 10^-12

=1×10^-12

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Which of the following elements is the most metallic
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We found cesium, strontium, aluminum, sulfur, chlorine, and fluorine on the periodic table. Cesium is the farthest left and the lowest, while fluorine is the farthest right and the highest, so we know they have the highest metallic character and the lowest metallic character, respectively.
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Complete the equation: monosaccharide + monosaccharide → ______ + water Complete the equation: monosaccharide + monosaccharide →
otez555 [7]

Answer: Disaccharides

Explanation:

Disaccharides can be defined as the combination of two monosaccharides which combines together to form a disaccharides.

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7 0
3 years ago
A sample of an unknown compound is vaporized at 180.°C. The gas produced has a volume of 2010.mL at a pressure of 1.00atm, and i
stiv31 [10]

<u>Answer:</u> The molar mass of the given unknown compound is 50.5 g/mol.

<u>Explanation:</u>

To calculate the volume of water, we use the equation given by ideal gas, which is:

PV=nRT

or,

PV=\frac{m}{M}RT

where,

P = pressure of sample = 1.00 atm

V = volume of sample = 2010 mL = 2.010 L   (Conversion factor: 1 L = 1000 mL)

m = Given mass of unknown compound = 2.73 g

M = Molar mass of unknown compound = ? g/mol

R = Gas constant = 0.0820\text{ L atm }mol^{-1}K^{-1}

T = temperature of sample = 180^oC=[180+273]K=453K

Putting values in above equation, we get:

1.00atm\times 2.010L=\frac{2.73g}{M}\times 0.0820\text{ L atm }mol^{-1}K^{-1}\times 453K\\\\V=50.45g/mol

Rounding off to 3 significant figures, we get the molar mass to be 50.5 g/mol.

Hence, the molar mass of the given unknown compound is 50.5 g/mol.

8 0
3 years ago
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