Answer:
The answer to your question is 47.44 g of Oxygen
Explanation:
Data
mass of Ammonia = 14.4 g
mass of Oxygen = ?
Balanced chemical reaction
4NH₃ + 7O₂ ⇒ 4NO₂ + 6H₂O
Process
1.- Calculate the molar mass of Ammonia
NH₃ = 4[(1 x 14) + (3 x 1)] = 4[14 + 3] = 4[17] = 68 g
2.- Calculate the molar mass of Oxygen
O₂ = 7[16 x 2] = 7[32] = 224 g
3.- Use proportions to calculate the mass of Oxygen
68g of NH₃ --------------------- 224 g of O₂
14.4 g of NH₃ ----------------- x
x = (14.4 x 224) / 68
x = 3225.6/ 68
x = 47.44 g
Iron is the heaviest element produced in large stars by nuclear fusion near the end of their life cycle .
<h3>What do you mean by the nuclear fusion ?</h3>
Nuclear fusion is the process by which two light atomic nuclei combine to form a single heavier one while releasing massive amounts of energy.
The main advantage of nuclear fusion is it is safe source for the generation of electricity.
Characteristics of nuclear fusion -:
- The main characteristic of nuclear fusion is that it involves formation of a singular particle from two or more atoms.
- Unlike nuclear fission, nuclear fusion is common in nature- just hard to recreate.
- Nuclear fusion typically produces few radioactive particles .
- Fusion works by applying a great deal of pressure to overcome .
Hence ,Iron is the heaviest element produced in large stars by nuclear fusion near the end of their life cycle .
Learn more about nuclear fusion ,here:
brainly.com/question/12701636
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The average atomic mass is calculated by the expression:
Average atomic mass = Σzₓ(Aₓ)
where zₓ is the relative abundance of an isotope and Aₓ is the atomic mass of the isotope.
We calculate the mass of the isotope as follows:
10.81 = .1980 (10.012938) + .8020 (x)
x = 11.00 -----------> mass of the isotope
<span>0.228 g
The balance formula for the reaction between SrH2 and H2O is
SrH2(s) + 2 H2O(l) ==> Sr(OH)2(s) + 2 H2(g)
So for every mole of SrH2 used, 2 moles of hydrogen gas, or 4 moles of hydrogen atoms are released. So let's calculate the molar mass of SrH2 and H2O so see what the limiting reactant is.
strontium = 87.62
Hydrogen = 1.00794
Oxygen = 15.999
Molar mass of SrH2 = 87.62 + 2 * 1.00794 = 89.63588 g/mol
Molar mass of H2O = 2 * 1.00794 + 15.999 = 18.01488 g/mol
Moles of SrH2 = 5.06 g / 89.63588 g/mol = 0.056450609 mol
Moles of H2O = 4.34 g / 18.01488 g/mol = 0.240911957 mol
Looking at the balanced formula, for every mole of SrH2, it takes 2 moles of H2O. So the limiting reactant will be the SrH2. And for every mole of SrH2 used, we get 4 moles of hydrogen atoms. So
4 * 0.056450609 mole * 1.00794 g/mole = 0.227595307 g
Since we only have 3 significant figures, round the result to 3 figures, giving
0.228 g</span>
