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vlada-n [284]
2 years ago
9

Liquid X is known to have a lower viscosity and lower surface tension than Liquid Y Use these facts to predict the result of eac

h experiment in the table below, if you can. experiment predicted outcome O mx will be greater than my O mx will be less than my O Ill y will be equal to my Wax-coated particles carefully put onto the surface of Liquid X or Liquid Y will stay on the surface, if the particles are small enough. The heaviest mass of particle x and my that will stay on each liquid's surface without sinking are measured. It's impossible to predict whether mx or my will be greater without more information. OFx will be greater than F)y 15.0 mL of Liquid X are poured into a beaker, and 15.0 mL of Liquid Y are poured FX will be less than Fr into an identical beaker. Stirrers in each beaker are connected to motors, and thewill be equal to P forces Fx and Fy needed to stir each liquid It's impossible to predict whether Fr or F will at a constant rate are measured. be greater without more information.
Chemistry
1 answer:
Dima020 [189]2 years ago
8 0
Liquid is safe i think hope this helps
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10. In which of the following is the symbol for the ion and the total number of electrons it contains given correctly?
dalvyx [7]

Answer:

10. D

9. A

8. A or B

Explanation:

10. Calcium has 20 electrons, but the Calcium ion has 18 electrons.

9. The mass of electrons are negligible.

8. Electrons have a very small mass where some consider it to have no mass.

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3 years ago
I need help on this asap
dlinn [17]
1.hydrogen
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Let’s suppose I place a live mouse in closed chambers with a CO2 sensor. In Chamber A, the mouse was given caffeine; therefore t
adell [148]

Answer:

Explanation:

Chamber

6 0
3 years ago
Let us write the appropriate equilibria and associate the correction <img src="https://tex.z-dn.net/?f=K_b" id="TexFormula1" tit
rosijanka [135]

Explanation:

The relation between K_a\&K_b is given by :

K_w=K_a\times K_b

Where :

K_w=1\times 10^{-14} = Ionic prodcut of water

The value of the first ionization constant of sodium sulfite = K_{a1}=1.4\times 10^{-2}

The value of K_{b1}:

1\times 10^{-14}=1.4\times 10^{-2}\times K_{b1}

K_{b1}=\frac{1\times 10^{-14}}{1.4\times 10^{-2}}=7.1\times 10^{-13}

The value of the second ionization constant of sodium sulfite = K_{a2}=6.3\times 10^{-8}

The value of K_{b2}:

1\times 10^{-14}=6.3\times 10^{-8}\times K_{b1}

K_{b1}=\frac{1\times 10^{-14}}{6.3\times 10^{-8}}=1.6\times 10^{-7}

3 0
3 years ago
SO
Burka [1]

Answer:

\large \boxed{\text{E) 721 K; B) 86.7 g}}

Explanation:

Question 7.

We can use the Combined Gas Laws to solve this question.

a) Data

p₁ = 1.88 atm; p₂ = 2.50 atm

V₁ = 285 mL;  V₂ = 435 mL

T₁ = 355 K;     T₂ = ?

b) Calculation

\begin{array}{rcl}\dfrac{p_{1}V_{1}}{T_{1}}& =&\dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{1.88\times285}{355} &= &\dfrac{2.50\times 435}{T_{2}}\\\\1.509& = &\dfrac{1088}{T_{2}}\\\\1.509T_{2} & = & 1088\\T_{2} & = & \dfrac{1088}{1.509}\\\\ & = & \textbf{721K}\\\end{array}\\\text{The gas must be heated to $\large \boxed{\textbf{721 K}}$}

Question 8. I

We can use the Ideal Gas Law to solve this question.

pV = nRT

n = m/M

pV = (m/M)RT = mRT/M

a) Data:

p = 4.58 atm

V = 13.0 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 385 K

M = 46.01 g/mol

(b) Calculation

\begin{array}{rcl}pV & = & \dfrac{mRT}{M}\\\\4.58 \times 13.0 & = & \dfrac{m\times 0.08206\times 385}{46.01}\\\\59.54 & = & 0.6867m\\m & = & \dfrac{59.54}{0.6867 }\\\\ & = & \textbf{86.7 g}\\\end{array}\\\text{The mass of NO$_{2}$ is $\large \boxed{\textbf{86.7 g}}$}

7 0
3 years ago
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