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ollegr [7]
3 years ago
6

Complete the equation: monosaccharide + monosaccharide → ______ + water Complete the equation: monosaccharide + monosaccharide →

______ + water disaccharide polypeptide polysaccharide fat
Chemistry
1 answer:
otez555 [7]3 years ago
7 0

Answer: Disaccharides

Explanation:

Disaccharides can be defined as the combination of two monosaccharides which combines together to form a disaccharides.

These are formed by the combination of sugars. The process is hydrolysis as it releases water after the reaction is complete.

Two monosachrrides are joined together by the glycosidic linkage. Some common examples are maltose, sucrose and lactose.

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As a technician in a large pharmaceutical research firm, you need to produce 300. mL of 1.00 M a phosphate buffer solution of pH
tamaranim1 [39]

Answer:  pH = 7.36. The pKa of H2PO4− is 7.21.

Explanation:

4 0
3 years ago
Can someone solve this question please​
kolbaska11 [484]

Answer:

I can't see the question

Explanation:

3 0
2 years ago
The solubility of nitrogen gas at 25 degrees C and 1 atm is 6.8 x 10^(-4) mol/L. If the partial pressure of nitrogen gas in air
Zolol [24]

Answer:

5.2 x 10⁻⁴ M.

Explanation:

  • The relationship between gas pressure and the  concentration of dissolved gas is given by  Henry’s law:

<em>P = kC</em>

where P is the partial pressure of the gaseous  solute above the solution.

k is a constant (Henry’s constant).

C is the concentration of the dissolved gas.

  • At two different pressures, there is two different concentrations of dissolved gases and is expressed in a relation as:

<em>P₁C₂ = P₂C₁,</em>

P₁ = 1.0 atm, C₁ = 6.8 x 10⁻⁴ mol/L.

P₂ = 0.76 atm, C₂ = ??? mol/L.

<em>∴ C₂ = (P₂C₁)/P₁ =</em> (0.76 atm)(6.8 x 10⁻⁴ mol/L)/(1.0 atm) = <em>5.168 x 10⁻⁴ mol/L ≅ 5.2 x 10⁻⁴ M.</em>

5 0
3 years ago
What is the molality of a solution containing 10.0 G of NA2 S04 and 1000.0 G of water
galina1969 [7]

Explanation:

1 literThe total of water is equal to 1000.0 g of water

we need to find the molality of a solution containing 10.0 g of dissolved in  Na₂S0₄1000.0 g of water

1. For that find the molar mass

Na:  2 x 22.99= 45.98

S:  32.07

O:  4 x 16= 64

The total molar mass is 142.05

We have to find the number of moles, y

To find the number of moles divide 10.0g by 142.05 g/mol.

So the number of moles is 0.0704 moles.

For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.

The molarity would end up being 0.0704 M

The molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is  0.0704 Mliter

7 0
2 years ago
write a generalization correlating solubility with ionization. start with: "as compounds become more ionized,..."
Tema [17]

Answer:

the solubility increases

Explanation:

The solubility of any ionic compound is due to the ionization of the compound and then the strong ion-dipole interactions acting between the ions and the solvent.

Thus, solubility also depends on the extent of the ionization of the salt.

The more the salt ionizes, the more there is ion-dipole interaction between the ions the solvent and more is the solubility.

4 0
3 years ago
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