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Sliva [168]
2 years ago
11

Seasonal changes in water temperature tend to remain within a narrow range. This is opposed to air temperature, which tends to f

luctuate across a wide range. The relative stability of ocean temperatures helps to regulate the temperatures of coastal regions. Why can water remain within a narrow range of temperatures?
A.
It reflects heat and does not absorb heat.
B.
It is only stable within a small temperature range.
C.
It has a high heat capacity.
D.
It is mobile and this allows heated water to sink.
Its C. i just did it
Chemistry
2 answers:
BartSMP [9]2 years ago
8 0

Answer:

Its C

Explanation:

Ok. You really know how.

jeka942 years ago
8 0

Answer:

the answer would be b

Explanation:

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Irina-Kira [14]
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5 0
2 years ago
A monoprotic weak acid when dissolved in water is 0.66% dissociated and produces a solution with a pH of 3.04. Calculate the Ka
raketka [301]

Answer:

Ka = 6.02x10⁻⁶

Explanation:

The equilibrium that takes place is:

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  • Ka = [H⁺][A⁻]/[HA]

We <u>calculate [H⁺] from the pH</u>:

  • pH = -log[H⁺]
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Keep in mind that [H⁺]=[A⁻].

As for [HA], we know the acid is 0.66% dissociated, in other words:

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We <u>calculate [HA]</u>:

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Finally we <u>calculate the Ka</u>:

  • Ka = \frac{[9.12x10^{-4}]*[9.12x10^{-4}]}{[0.138]} = 6.02x10⁻⁶
3 0
2 years ago
Consider a balloon with volume V. It contains n moles of gas and has an internal pressure of P. The temperature of the gas is T.
Maksim231197 [3]

Answer:

V₂ = 0.6 V.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

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n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n is constant, and have different values of P, V and T:

<em>(P₁V₁T₂) = (P₂V₂T₁).</em>

<em></em>

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<em>∴ V₂ = (P₁V₁T₂)/(P₂T₁) =</em> (P)(V)(0.75 T)/(1.25 P)(T)<em> = 0.6 V.</em>

3 0
3 years ago
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