To have a force of 3.8x10-8 the two chaarges must be 0.65m apart.
Answer:
a)
, b)
, c) 
Explanation:
a) The linear acceleration of the watermelon seed is:

![a_{r} = \left[\left(33\,\frac{rev}{min} \right)\cdot \left(2\pi\,\frac{rad}{rev} \right)\cdot \left(\frac{1}{60}\,\frac{min}{s} \right)\right]^{2}\cdot (0.023\,m)](https://tex.z-dn.net/?f=a_%7Br%7D%20%3D%20%5Cleft%5B%5Cleft%2833%5C%2C%5Cfrac%7Brev%7D%7Bmin%7D%20%5Cright%29%5Ccdot%20%5Cleft%282%5Cpi%5C%2C%5Cfrac%7Brad%7D%7Brev%7D%20%5Cright%29%5Ccdot%20%5Cleft%28%5Cfrac%7B1%7D%7B60%7D%5C%2C%5Cfrac%7Bmin%7D%7Bs%7D%20%5Cright%29%5Cright%5D%5E%7B2%7D%5Ccdot%20%280.023%5C%2Cm%29)

b) The watermelon seed is experimenting a centrifugal acceleration. The coefficient of static friction between the seed and the turntable is calculated by the Newton's Laws:





c) Angular acceleration experimented by the turntable is:



The tangential acceleration experimented by the watermelon seed is:


The linear acceleration experimented by the watermelon seed is:



The minimum coefficient of static friction is:


Answer:
W = 53.6648 J
Explanation:
W = ∫ F * dr
F = < 4*x i , 3*y j > Newtons
dr = < dx, 0 >
Take the dot product:
F * dr = 4* x * dx
Now replacing numeric
W = ∫ 4 * x * dx , ║ x = ( 0 m ⇒ 5.18 m )
W = ¹ / ₂ * (4 N/m) * x ²
W = (2 N/m) * (5.18 m)²
W = 53.6648 J
Answer:
Fc = 89.67N
Explanation:
Since the rope is unstretchable, the total length will always be 34m.
From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:
L1+L2=34m
Replacing this value in the previous equation:
Solving for H:

We can now, calculate the angle between L1 and the 2m segment:

If we make a sum of forces in the midpoint of the rope we get:
where T is the tension on the rope and F is the exerted force of 87N.
Solving for T, we get the tension on the rope which is equal to the force exerted on the car:
