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STatiana [176]
3 years ago
9

A force of 75 N is applied to a spring, causing it to stretch 0.3 m. What is the spring constant of the spring?

Physics
1 answer:
muminat3 years ago
3 0
The answer is D. 250 N/m <span />
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F_{wood} - F_{oil} - F_{water} = 0\\\\\rho _{wood} .gh - \rho _o .g(h-x) - \rho_w .gx = 0\\\\\rho _{wood} .h - \rho _o (h-x) - \rho_w .x = 0\\\\\rho _{wood} .h -\rho _o h + \rho _o x - \rho_w .x =0\\\\h (\rho _{wood}  -\rho _o ) = x( \rho_w - \rho _o)\\\\x =h[\frac{ \rho _{wood}  -\rho _o }{\rho_w - \rho _o} ]\\\\x = 3.69\ cm \times [\frac{974 - 926}{1000-926} ]\\\\x = 2.39 \ cm

Therefore, the position of the wood below the interface of the two liquids is 2.39 cm.

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3 years ago
If a creature cats Ferrari, with an initial speed of 10 m/s, accelerate at a rate of 50 m/s/s for 3 seconds, what will it's fina
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160 m/s because you start off with 10 and go up by 50*3 which is 150 then add that with the begging speed to achieve 160m/s.

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3 years ago
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