A force of 75 N is applied to a spring, causing it to stretch 0.3 m. What is the spring constant of the spring?
1 answer:
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Answer:
5.4 J.
Explanation:
Given,
mass of the object, m = 2 Kg
initial speed, u = 5 m/s
mass of another object,m' = 3 kg
initial speed of another orbit,u' = 2 m/s
KE lost after collusion = ?
Final velocity of the system
Using conservation of momentum
m u + m'u' = (m + m') V
2 x 5 + 3 x 2 = ( 2 + 3 )V
16 = 5 V
V = 3.2 m/s
Initial KE =
=
= 31 J
Final KE =
Loss in KE = 31 J - 25.6 J = 5.4 J.