Answer:
The top of the window is 0.5 m below the sill of the upper window
Explanation:
We have the time the pot takes to fall a distance y- yo = 2.0 m and g = 9.8, from this we can calculate the velocity of the pot when it just reached the top of the window in question. Take the positive y direction to be downward
y-yo=vo*t+I/2gt^2
vo=(y-yo-I/2gt^2)/t
vo=3.138 m/s
The flowerpot falls from rest and we have the velocity it gains until it reaches the top of the window below, from this information we can get the distance between the sill and the top of the window below.
v^2=vo^2+2g(y-yo)
y-yo=(v^2-vo^2)/2g
= 0.5 m
The top of the window is 0.5 m below the sill of the upper window
<span>The current system of units has three standard units: The meter, kilogram, and second. These three units form the mks-system or the metric system. A meter is a unit of length, currently defined as the distance light travels within 1/299782458th of a second. A kilogram is a unit of mass.</span>
Try calculating maybe that would help you
