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Rina8888 [55]
3 years ago
7

If the torque on an object adds up to zero Group of answer choices the object is at rest. the object cannot be turning. the obje

ct could be accelerating linearly but it could not be turning. the forces on it also add up to zero. the object could be both turning and accelerating linearly.
Physics
1 answer:
garik1379 [7]3 years ago
8 0

Answer:

the body has linear acceleration, but cannot rotate

Explanation:

Let's analyze the system

If the torque is zero, the two forces are the same magnitude, but applied to each side of the body in such a way that the torque cancels the punch of the other. Therefore the body cannot turn

The two forces go in the same direction so the object can have linear acceleration

The object is at rest because it has a force in the same direction, but in the opposite direction.

therefore the correct answer is:

the body has linear acceleration, but cannot rotate

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How would you find the speed of a person who walked
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Answer:

v = 1.25 m/s

Explanation:

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Time taken by him to cover that distance is 8 seconds.

If we want to find the speed of a person, we must know distance covered by it and taken. In this case, we know both distance and time. His speed is given by :

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3 years ago
Two uniform solid cylinders, each rotating about its central (longitudinal) axis, have the same mass of 2.88 kg and rotate with
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(a) K_{small}=4839.3J

(b) K_{larger}=17406.4J

Explanation:

Given data

The angular velocity of two cylinders ω=257 rad/s

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The radius of small cylinder r₁=0.319 m

The radius of larger cylinder r₂=0.605 m

For Part (a)

The rotational kinetic energy of the cylinder is given by:

K=\frac{1}{2}Iw^2

Where I is rotational of inertia of solid cylinder about its central axis.

So

K=\frac{1}{2}Iw^2\\ K=\frac{1}{2}(1/2mr^2)w^2

Substitute the given values

So

K_{small}=\frac{1}{4}(2.88kg)(0.319)^2(257rad/s)^2 \\K_{small}=4839.3J

For Part (b)

K=\frac{1}{2}Iw^2\\ K=\frac{1}{2}(1/2mr_{2}^2)w^2

Substitute the given values

K_{larger}=\frac{1}{4}mr_{2}^2w^2\\ K_{larger}=\frac{1}{4}(2.88kg)(0.605m)^2(257rad/s)^2\\ K_{larger}=17406.4J

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3 years ago
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Answer:

Because 'distance per second' is a velocity, not an acceleration.

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