If there's enough Hydrogen in the cloud, then fusion reactions
will ignite in the core, and it'll become a star.
The formula for half-life is:
![A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h}}](https://tex.z-dn.net/?f=A_%7Bfinal%7D%3DA_%7Binitial%7D%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B%5Cfrac%7Bt%7D%7Bh%7D%7D)
Where A is the amount of iodine-131 initially and after 40 days, t is time, h is half-life of the isotope. Let's plug in our values to the equation:
![A_{final}=20(\frac{1}{2})^{\frac{40}{8}=0.625g](https://tex.z-dn.net/?f=A_%7Bfinal%7D%3D20%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B%5Cfrac%7B40%7D%7B8%7D%3D0.625g)
Therefore, the patient has 0.625 grams of iodine-131 after 40 days.
Answer:
The necessary information is if the forces acting on the block are in equilibrium
The coefficient of friction is 0.577
Explanation:
Where the forces acting on the object are in equilibrium, we have;
At constant velocity, the net force acting on the particle = 0
However, the frictional force is then given as
F = mg sinθ
Where:
m = Mass of the block
g = Acceleration due to gravity and
θ = Angle of inclination of the slope
F = 5×9.81×sin 30 = 24.525 N
Therefore, the coefficient of friction is given as
24.525 N = μ×m×g × cos θ = μ × 5 × 9.81 × cos 30 = μ × 42.479
μ × 42.479 N= 24.525 N
∴ μ = 24.525 N ÷ 42.479 N = 0.577
Answer:
option (B)
Explanation:
Intensity of unpolarised light, I = 25 W/m^2
When it passes from first polarisr, the intensity of light becomes
![I'=\frac{I_{0}}{2}=\frac{25}{2}=12.5 W/m^{2}](https://tex.z-dn.net/?f=I%27%3D%5Cfrac%7BI_%7B0%7D%7D%7B2%7D%3D%5Cfrac%7B25%7D%7B2%7D%3D12.5%20W%2Fm%5E%7B2%7D)
Let the intensity of light as it passes from second polariser is I''.
According to the law of Malus
![I'' = I' Cos^{2}\theta](https://tex.z-dn.net/?f=I%27%27%20%3D%20I%27%20Cos%5E%7B2%7D%5Ctheta)
Where, θ be the angle between the axis first polariser and the second polariser.
![I'' = 12.5\times Cos^{2}15](https://tex.z-dn.net/?f=I%27%27%20%3D%2012.5%5Ctimes%20Cos%5E%7B2%7D15)
I'' = 11.66 W/m^2
I'' = 11.7 W/m^2
Answer: Option (A) is the correct answer.
Explanation:
A corrective action is defined as the action with the help of which a person can avoid a difficulty or problem that he/she was facing earlier.
For example, when the chef checked the temperature of soup using thermometer then it was 120 but his operation's critical limit was 135.
So, to avoid this problem he heated the soup to 165 at 15 seconds following which he got the result as desired.
Therefore, reheating the soup was his corrective action.
Thus, we can conclude that reheating the soup was the corrective action.