Answer:
This is an attempt to more clearly visualize the nature of single slit diffraction. The phenomenon of diffraction involves the spreading out of waves past openings which are on the order of the wavelength of the wave.
Explanation:
Divide
(the distance covered in some period of time)
by
(the time taken to cover the distance).
The quotient is the average speed during that period of time.
Answer:
180° C
Explanation:
First we start by finding the area of the stopper.
A = πd²/4, where d = 1.5 cm = 0.015 m
A = 3.142 * 0.015² * ¼
A = 1.767*10^-4 m²
Next we find the force on the stopper
F = (P - P•)A, where
F = 10 N
P = pressure inside the tube,
P• = 1 atm
10 = (P - 101325) * 1.767*10^-4
P - 101325 = 10/1.767*10^-4
P - 101325 = 56593
P = 56593 + 101325
P = 157918 Pascal
Now, remember, in an ideal gas,
P1V1/T1 = P2V2/T2, where V is constant, then we have
P1/T1 = P2/T2, and when we substitute the values, we have
101325/(273 + 18) = 157918/ T2
101325/291 = 157918/ T2
T2 = (157918 * 291)/101325
T2 = 453 K
T2 = 453 - 273 = 180° C
the equation of the tangent line must be passed on a point A (a,b) and
perpendicular to the radius of the circle. <span>
I will take an example for a clear explanation:
let x² + y² = 4 is the equation of the circle,
its center is C(0,0). And we assume that the tangent line passes to the point
A(2.3).
</span>since the tangent passes to the A(2,3), the line must be perpendicular to the radius of the circle.
<span>Let's find the equation of the line parallel to the radius.</span>
<span>The line passes to the A(2,3) and C (0,0). y= ax+b is the standard form of the equation. AC(-2, -3) is a vector parallel to CM(x, y).</span>
det(AC, CM)= -2y +3x =0, is the equation of the line // to the radius.
let's find the equation of the line perpendicular to this previous line.
let M a point which lies on the line. so MA.AC=0 (scalar product),
it is (2-x, 3-y) . (-2, -3)= -4+4x + -9+3y=4x +3y -13=0 is the equation of tangent
