What does the quotient rule of exponents say?

NEED THE ANSWER ASAP

Kisachek [45]

Answer:

c = 7 $\sqrt{3}$

Step-by-step explanation:

Using the sine ratio in the left right triangle and the exact value

sin45° = $\frac{\sqrt{2} }{2}$ , then

sin45° = $\frac{opposite}{hypotenuse}$ = $\frac{a}{7\sqrt{2} }$ = $\frac{\sqrt{2} }{2}$ ( cross- multiply )

2a = 14 ( divide both sides by 2 )

a = 7

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Using the tangent ratio in the right triangle and the exact value

tan30° = $\frac{1}{\sqrt{3} }$ , then

tan30° = $\frac{opposite}{adjacent}$ = $\frac{a}{c}$ = $\frac{7}{c}$ = $\frac{1}{\sqrt{3} }$ ( cross- multiply )

c = 7 $\sqrt{3}$

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4 0

4 years ago

How to solve it this problem

nikdorinn [45]

The question asks us to find m∠ABC. We know that ray BD is a bisector of ∠ABC. So, all we need to do now is equate the expressions of ∠ABD and ∠DBC to the expression of ∠ABC. Here is what we get from this:
$(9x-7)+(3x+17) = 16x-2$
Now, just solve for x. When doing so, we get the answer x = 3. Since we have the value for x, all we need to do is plug in that value to the expression for ∠ABC, which would result in 46. This means that the answer to your query is ∠ABC = 46°. Hope this helps and have a phenomenal day!

5 0

4 years ago

99 Points Need Help! How to reflect over y= -x+6

iragen [17]

To reflect in the line y = -x + 6, we translate everything down 6 first. This will make it seem like we are reflecting in the line y = -x
                                 (x,y) → (x, y-6)
Then, to reflect in the line y = -x, we switch the x- and y-coordinates and then make them negative
                                 (x,y) → (-(y-6), -x)
Then we move everything back up again
                                 (x,y) → (-(y-6), -x + 6)
I will present to you an example. Reflect the point (-4, 8) in the line y = -x + 6.
                                 (-4,8) → (-(8-6), -(-4) + 6) → (-2, 10)
You should graph this out to confirm with the reflection line.

6 0

3 years ago

Read 2 more answers

Roland was driving to campus but realized that his car is out of gas. He started driving around Syracuse looking for a gas stati

tester [92]

Answer:

Roland is right, he can be 95% sure that average gas prices have gone up since the same time last year.

Step-by-step explanation:

Let μ be average gas price around Syracuse.

Then hypotheses are:

$H_{0}:$ μ = $2.68

$H_{a}:$ μ > $2.68

Then test statistic can be calculated as:

z= $\frac{X-M}{\frac{s}{\sqrt{N} } }$ where

X is the Roland's calculated average gas prices of 50 gas stations ($2.74)

M is the average average gas prices in the entire of Syracuse last year

s is the standard deviation ($0.11)

N is the sample size(50)

Then z= $\frac{2.74-2.68}{\frac{0.11}{\sqrt{50} } }$ ≈ 3.86

Since P-value of test statistic ≈ 0.00006 <0.05 (significance level), we can reject the null hypothesis.

7 0

4 years ago

Vail Resorts pays part-time seasonal employees at ski resorts on an hourly basis. At a certain mountain, the hourly rates have a

notsponge [240]

Answer:

$z=0.842$

And if we solve for a we got

$\mu=13.16 +0.842*3=15.69$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the hourly rates of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,3)$

For this part we want to find a value a, such that we satisfy this condition:

$P(X>13.16)=0.20$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.80 of the area on the left and 0.20 of the area on the right it's z=0.842. On this case P(Z<0.842)=0.8 and P(z>0.842)=0.20

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=0.842$

And if we solve for a we got

$\mu=13.16 +0.842*3=15.69$

3 0

3 years ago