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rosijanka [135]
3 years ago
15

99 Points Need Help! How to reflect over y= -x+6

Mathematics
2 answers:
Kay [80]3 years ago
8 0

   (x,y) → (-(y-6), -x + 6)  

iragen [17]3 years ago
6 0
To reflect in the line y = -x + 6, we translate everything down 6 first. This will make it seem like we are reflecting in the line y = -x
                                 (x,y) → (x, y-6)
Then, to reflect in the line y = -x, we switch the x- and y-coordinates and then make them negative
                                 (x,y) → (-(y-6), -x)     
Then we move everything back up again
                                 (x,y) → (-(y-6), -x + 6)          
I will present to you an example. Reflect the point (-4, 8) in the line y = -x + 6.
                                 (-4,8) → (-(8-6), -(-4) + 6) → (-2, 10)
You should graph this out to confirm with the reflection line.
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Step-by-step explanation:

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Lera25 [3.4K]

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<em>"6" and "3" cancels out as well as the "x"s and "y"s. Shown below</em>:

\frac{6x^{2}y^3}{3xy}\\=2xy^2

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