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lara31 [8.8K]
3 years ago
14

Amélie runs a bakery. She wants to find out whether her cake sales are affected by the weather conditions. She recorded the dail

y temperature and the number of cakes she sold on different days of the year. The table shows the data she gathered. Daily Temperature (°F) Cakes Sold 42 39 45 52 48 31 54 61 59 72 62 35 64 61 65 34 67 58 75 45 84 24
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
6 0

Answer:

Step-by-step explanation:

Daily temp(in F) Cakes sold

 

42 39

45 52

48 31

54 61

59 72

62 35

64 61

65 34

67 58

75 45

84 24

To find whether there is an association between these two let us find the correlation coefficient between these two variables.

r=-0.1975

Since |r|<0.5, correlation is weak.  

Let us test the hypothesis r =0

H0:r=0

Ha:r not equals 0

Test statistic = \frac{r\sqrt{n-2} }{\sqrt{1-r^2} } \\=\frac{-0.1975\sqrt{11-2} }{\sqrt{1-0.1975^2} }\\=\frac{-0.5625}{{0.9803} } \\=-0.5738

p =0.298

Since p value >0.10, at 90% significance level we accept that there is no association.

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Answer:

b=\frac{79}{3} or b=26.33

Step-by-step explanation:

Assuming the question to be finding the value of b.

3+\frac{1}{3}=b-23

Solution:

Rewrite the equation as.

b-23=3+\frac{1}{3}

first we solve right side of the equation.

b-23=\frac{3\times 3+ 1}{3}

b-23=\frac{9+ 1}{3}

b-23=\frac{10}{3}

Add 23 both side of the equation.

b-23+23=\frac{10}{3}+23

b=\frac{10+23\times 3}{3}

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b=\frac{79}{3}

or

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Therefore, the value of b=\frac{79}{3} or b=26.33

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