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3 years ago

One number is six more than another number. The sum of their squares is 90.

1 answer:

3 0

First number: x
Second: x + 6
(x)^2 + (x + 6)^2 = 90
x^2 + x^2 + 6x + 6x + 36 = 90
Simplify more
2x^2 + 12x + 36 = 90
2x^2 + 12x - 54 = 0
2(x + 9)(x - 3) = 0
You know that x = -9, and 3
The first number is 3, the other -9

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Someone please help

svp [43]

Answer:

I got 25z^2−15z+2

Step-by-step explanation:

But if the answer shown is the correct answer, I think your computer read wrong, because those answers are the exact same :/

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K+3d=8c-8d solve for d

FromTheMoon [43]

Move k to the other side to isolate d.

So we will get 3d = 8c - 8d - k

Now divide both sides by 3 to isolate d.

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tamaranim1 [39]

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3 years ago

7.) Solve the system of equations below. -2x + 3y = 9 2/3x + 2y = 0

iren [92.7K]

Answer:

So lets isolate y

we have

-2x+3y=9

2/3x +2y=0

Im gonna do the first equation

so -2x + 3y = 9

Add 2x on both sides

3y= 9+ 2x

Now divide by 3 to isolate y

y= 3+ 2/3x

Now we can subsitute y into any eqaution (I’m gonna do the second one) to solve.

2/3x+ 2(3+ 2/3x)= 0

Solve:

2/3x+ 6 + 4/3x = 0

6/3x +6= 0

2x+6=0

2x= -4

x= -2

Now we can subsitute this for any equation.

so I’m gonna do the first equation

-2(-2)+3y=9

4+3y=9

3y= 5

y= 5/3

y= 1 2/3

Final answer:

x=-2

y= 1 2/3

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2 years ago