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3 years ago

Write as a polynomial: y^2(y+5)(y–3)

1 answer:

3 0

You mean expand

so first do the parnethesees bits becasue the rest can be done later

(y+5)(y-3)
foil aka distribute
y^2+5y-3y-15
y^2+2y-15

now remember tha tis all multilied by y^2
y^2(y^2+2y-15)
y^4+2y^3-15y^2

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Which products result in a perfect square trinomial? Select three. (-x+9)(-x-9), (xy+x)(xy+x), (2x-3)(-3+2x), (16-x^2)(x^2-16),

GrogVix [38]

Answer:

(2x-3)(-3+2x),(16-x^2)(x²-16),4y^2+25)(25+4y^2)

Step-by-step explanation:

I know that the rest of the products didn't make a perfect square cause they don´t aren´t squared,I also know that they are the odd ones out among the rest of the product so yeah,I am not too sure if I got it right...sorry if I didn´t.

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4 years ago

Kevin has $24 to buy a gift for his cousin he found a gift for $22 with 5% sales tax added on will Kevin have enough money to bu

DIA [1.3K]

Answer:

5% of $22 is $1.10.

22+1.10=23.10

23.10 is less than 24

Step-by-step explanation:

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3 years ago

The weather service recorded some temperatures in Baltimore and Seattle throughout the month of October. Which statement is

algol [13]

Answer:

A) The amount of spread in the middle-half of Baltimore's data is greater than Seattle's

Step-by-step explanation:

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3 years ago

Describe, in detail, when to use the law of cosines, the law of sines, and the law of sines with the ambiguous case. Provide gen

shutvik [7]

You can use the Law of Cosines, if only one of which is missing: three sides and one angle. Hence, if the known properties of the triangle is SSS(side-side-side) or SAS (side-angle-side), this law is applicable.

You can use the Law of Sines if you want to equate the ratio of the sine of an angle and its opposite side. This can be used if the known properties of the triangle is ASA(angle-side-angle) or SAS.

The ambiguous case is the SAS triangle. This could be easily solved using Law of Sines than Law of Cosines. Take for example: side a = 4, side b = 10, angle A = 23°. Then, we can determine angle B through Sine Law.

sin 23°/4 = sin B/10
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4 years ago

Suppose that P(A) = 0.4 and P(B) is unknown. (a) Is it possible that P(A and B) = 0.5? Explain why or why not. (b) Is it possibl

zhannawk [14.2K]

Answer and explanation:

Given : Suppose that P(A) = 0.4 and P(B) is unknown.

To find :

(a) Is it possible that P(A and B) = 0.5? Explain why or why not.

P(A) = 0.4

So, P(A and B) cannot be 0.5 because maximum value of P(A and B) is the lowest of P(A) and P(B).

The range of P(A and B) is 0 to 0.4.

Therefore, P(A and B) cannot be greater than P(A).

(b) Is it possible that P(A and B) = 0.3? Explain why or why not.

Yes, it is possible as P(A and B) = 0.3 < P(A)=0.4

(c) Is it possible that P(A or B) = 0.5? Explain why or why not.

Its is possible that P(A or B) = 0.05,

As P(A or B) can have a least value equal to highest of P(A) and P(B) and maximum value of P(A or B) is 1.

So, P(A or B) can be any value within the range 0.4 to 1.

(d) Is it possible that P(A or B) = 0.3? Explain why or why not.

P(A or B) cannot be 0.3 as the least value of P(A or B) is 0.4.

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3 years ago