The area of the "aob" secor is given by:
A = (S '/ S) * (pi) * (r ^ 2)
Where,
S '/ S = relation of arcs
r: radius of the circle
Substituting values we have:
A = (145/360) * (3.14) * (2 ^ 2)
A = 5.058888889
Rounding off we have:
A = 5.1 yd ^ 2
Answer:
the area of sector "aob" is:
A = 5.1 yd ^ 2
Slope for f(x):
Slope for g(x)
y = mx + b
y = 5x + 1
m = 5
The slope for f(x) is twice the slope of g(x).
B. f(x)'s y-intercept is -1 because y = -1 when x = 0. g(x)'s y-intercept is 1 because 1 is in the "b" spot in y = mx + b. g(x) has the greater y-intercept.
Answer:
3.15 ツ
Step-by-step explanation: