Take the derivative:
g’(x) = 12x^3 - 24x^2
Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)
x = 0 or x = 2
Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0
g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52
There is an absolute max at (0,0) or when x = 0
Answer:
need help too
Step-by-step explanation:
The answer is 1952 because you have to add all of the numbers together
125-45=M would be a simple way of writing the amount taken from the original
m∠A = 40
Step-by-step explanation:
Given AB =AC and m∠B = 70
Since AB =AC , Triangle ABC is an isosceles Triangle and the corresponding angles B and C are equal.
So m∠B = m∠C = 70
The sum of the 3 Angles of a triangle is 180°.
=> m∠A + m∠B + m∠C = 180
=> 140 + m∠C = 180
=> m∠C = 40
Hence the answer is m∠C = 40