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2 years ago

HELP PLEASE ! it keep saying its wrong

Mathematics

1 answer:

andre [41]2 years ago

7 0

Answer:

x=24 y=33

Step-by-step explanation:

If a diameter or radius is perpendicular to a chord, then it bisects the chord and its arc.

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Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

3 years ago

Which of the following numbers are irrational

Fed [463]

letter d is one of the irrational numbers

4 0

3 years ago

What is the order of operation in math expressions?

Gnom [1K]

Parenthases
Equation
Multiplication
Division
Addition
Subtraction

8 0

3 years ago

a cartographer used a scale of 1 inch :300 meters for the heights of different mountains if the actual height of one of those mo

zaharov [31]

Answer:

$12\frac{1}{3}$ inches

Step-by-step explanation:

So to go from 300 to 3700 you have to multiply by $12\frac{1}{3}$

7 0

3 years ago

Can someone help me ? Please thank you

Tom [10]

Correct answer is the 4th choice 16!!!

Hope this helps!!!

7 0

3 years ago

HELP PLEASE ! it keep saying its wrong ​

HELP PLEASE ! it keep saying its wrong