Making a shape bigger and smaller
Answer:
3
Step-by-step explanation:
3/4 (5x -3)+8=17
3/4 (5x -3) = 17 - 8 = 9
(5x -3) = 9 * (4/3)= 36/3 = 12
5x = 12 + 3 = 15
x = 3
Answer: The resultant would be the sum and the difference between the vectors.
Step by step explanation: 1. The possible resultant is between the sum of the 2 vectors and the difference between the two vectors.
2. The greatest magnitude is when the vectors lie in the same direction and the sum would be the scalar sum of the two vectors. The angle between the two would be zero degree.
Answer:
<h2>See below</h2>
Step-by-step explanation:
I can't drag and drop the graphs, but I can graph the equations shown. Then, all you will have to do is match the graphs shown the the graph that I will provide.
<h3>EQUATION 1: y = x² - 2</h3>
Graph Properties:
Opens up
Vertex is 0, -2
Axis of symmetry is x = 0
Graph photo shown in file called equation 1 graph
<h3>EQUATION 2: y = 2x²</h3>
Graph Properties:
Opens up
Vertex is 0, 0
Axis of symmetry is x = 0
Graph photo shown in file called equation 2 graph
<h3>EQUATION 3: y = (x - 2)²</h3>
Graph Properties:
Opens up
Vertex is 2, 0
Axis of symmetry is x = 2
Graph photo shown in file called equation 3 graph
I'm always happy to help :)
Answer:
a) 
b) 
c) 
With a frequency of 4
d) 
<u>e)</u>
And we can find the limits without any outliers using two deviations from the mean and we got:

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case
Step-by-step explanation:
We have the following data set given:
49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000
Part a
The mean can be calculated with this formula:

Replacing we got:

Part b
Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Part c
The mode is the most repeated value in the sample and for this case is:

With a frequency of 4
Part d
The midrange for this case is defined as:

Part e
For this case we can calculate the deviation given by:

And replacing we got:

And we can find the limits without any outliers using two deviations from the mean and we got:

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case