Ask question

Ask question

All categories

2 years ago

7

Yan is climbing down a ladder. Each time he descends four rungs on the ladder, he stops to see how much farther he has to go. Wh

ich word in the problem indicates that a negative integer should be used?
climbing

stops

descends

farther

2 answers:

Dmitriy789 [7]2 years ago

7 0

the answer is C

Descends

zavuch27 [327]2 years ago

4 0

C. Descends
Hope this helps!

You might be interested in

Line l is a perpendicular bisector of line segment A C. It intersects line segment A C at point B. Line l also contains points D

N76 [4]

Answer:

First one is DC

Second one is AB.

Step-by-step explanation:

Just did them on edge.

3 0

3 years ago

Read 3 more answers

Please solve these questions for me. i am having a difficult time understanding.

s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

1)

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

$\angle AED = \angel BEC$ ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

2)

Refer the attached figure

$\angle ABC = 90^{\circ}$

In ΔDBC

BC=DC (Given)

So, $\angle CDB=\angle DBC$ (Opposite angles of equal sides are equal)

So, $\angle CDB=\angle DBC=x$

So, $\angle CDB+\angle DBC+\angle BCD = 180^{\circ}$ (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So, $\angle CDB=\angle DBC=x = 65^{\circ}$

Now,

$\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90$

So, $\angle ABD=90-x=90-65=25^{\circ}$

In ΔABD

AB = BD (Given)

So, $\angle BAD=\angle BDA$ (Opposite angles of equal sides are equal)

So, $\angle BAD=\angle BDA=y$

So, $\angle BAD+\angle BDA+\angle ABD = 180^{\circ}$ (Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0

3 years ago

Solving systems of equations<br><br> X-2y=0<br> Y=2x-3

bearhunter [10]

$\left \{ {{x-2y=0} \atop {y=2x-3}} \right. \\\\Substitute\ second\ equation\ to\ first:\\\\x-2(2x-3)=0\\x-4x+6=0\\-3x=-6\ \ \ \ \ |:-3\\x=2\\\\y=2\cdot2-3\\y=4-3=1\\\\ \left \{ {{y=1} \atop {x=2}} \right.$

5 0

3 years ago

Read 2 more answers

Determine the unknown angle measures, to the nearest degree, in the diagram provided.

serg [7]

Answer:

a is <u>5</u><u>3</u><u>.</u><u>8</u><u>°</u><u>,</u> and b is <u>3</u><u>6</u><u>.</u><u>2</u><u>°</u>

Step-by-step explanation:

Using sine trig rule:

${ \boxed{ \bf{ \sin(b) = \frac{opposite}{hypotenuse} }}}$

${ \tt{ \sin(b) = \frac{78}{132} }} \\ \\ { \tt{b = { \sin }^{ - 1}( \frac{78}{132} ) }} \\ \\ { \tt{b = 36.2 \degree}}$

Summation of angles of triangle:

${ \tt{a + b + 90 \degree = 180 \degree}} \\ { \tt{a + 36.2 \degree + 90 \degree = 180 \degree}} \\ { \tt{a = (180 - 36.2 - 90) \degree}} \\ { \tt{a = 53.8 \degree}}$

7 0

2 years ago

You have a kite whose diagnoals are 8 m and 22 m. Find the area of the kite. Show all of your work.

Wittaler [7]

-----------------------------
Formula
-----------------------------
$\text {Area of a kite = } \dfrac{pq}{2} \text { where p and q are the diagonals }$

-----------------------------
Find Area
-----------------------------

$\text {Area = } \dfrac{8 \times 22}{2}$

$\text {Area = } \dfrac{176}{2}$

$\text {Area = } 88 \ m^{2}$

-----------------------------
Answer: Area = 88m²
-----------------------------

6 0

3 years ago