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DochEvi [55]
3 years ago
6

NEED HELP WITH TRIG please show work as i am trying to learn the material i'm really puzzled. its soh cah toa but i don't rememb

er how to do it

Mathematics
2 answers:
natulia [17]3 years ago
8 0

Answer:

see below

Step-by-step explanation:

5.  sin 31 = opp/ hyp

  sin 31 = 34 /x

x = 34 / sin 31

x =66.0145369

tan 31 = opp /adj

tan 31    = 34/y

y = 34/ tan 31

y= 56.5855024

6.  Pythagorean theorem to find z

9^2+12^2 = z^2

81+144 = z^2

225 = z^2

z =sqrt(225) =15

sin x = opp / hyp

sin x = 9/15

take the inverse sin

x = sin^ -1 (9/15) = 36.86989765

sin y = opp / hyp

sin y = 12/15

take the inverse sin

y = sin^ -1 (12/15) = 53.13010235

daser333 [38]3 years ago
3 0

Answer:

1. sin(31) = opposite/hypotenuse

sin(31) = 34/x

x = 34/sin(31) = 66.0145369

x = 66.0°

tan(31) = opposite/adjacent

tan(31) = 34/y

y = 34/tan(31) = 56.5855024

y = 56.6°

2. tan(x) = opposite/adjacent

tan(x) = 9/12

x = 36.86989765

x = 36.9°

y = 180 - 90 - x

y = 53.13010235

y = 53.1°

z² = 9² + 12²

z² = 225

z = 15

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ohaa [14]
Pick 2 points on ur line and use the slope formula : (y2 - y1) / (x2 - x1)

(y2 - y1) / (x2 - x1)
(-9,0)....x1 = -9 and y1 = 0
(0,6).... x2 = 0 and y2 = 6
now sub
slope = (6 - 0) / (0 - (-9) = 6/(0 + 9) = 6 / 9 = 2/3 <==

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5 0
3 years ago
If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°
Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = c^{2} = a^{2} + b^{2}

a = 7 and b = 11

a^{2} = 49

b^{2} = 121

Plugging in the values, we will get:

c^{2} = 49 + 121

c^{2} = 170

c = \sqrt{170}

To calculate the unknown angle B, we can use law of sine.

Law of sine = \frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

So,

\frac{c}{sinC} = \frac{b}{sinB}

\frac{\sqrt{170} }{sin90} =  \frac{11}{sinB}

Sin90 = 1

sinB = \frac{11}{\sqrt{170} }

B = sin^{-1} (\frac{11}{\sqrt{170} })

B = 57.5°

8 0
3 years ago
Need help #1. The answer is shown, but I don’t know how to get to the answer. Please teach and show steps.
Rufina [12.5K]

Answer:

B

Step-by-step explanation:

We are given that <em>x</em> and <em>y</em> are functions of time <em>t</em> such that <em>x</em> and <em>y</em> is a constant. So, we can write the following equation:

x(t)+y(t)=k,\text{ where $k$ is some constant}

The rate of change of <em>x</em> and the rate of change of <em>y</em> with respect to time <em>t</em> is simply dx/dt and dy/dt, respectively. So, we will differentiate both sides with respect to <em>t: </em>

<em />\displaystyle \frac{d}{dt}\Big[x(t)+y(t)\Big]=\frac{d}{dt}[k]<em />

Remember that the derivative of a constant is always 0. Therefore:

\displaystyle \frac{dx}{dt}+\frac{dy}{dt}=0

And by subtracting dy/dt from both sides, we acquire:

\displaystyle \frac{dx}{dt}=-\frac{dy}{dt}

Hence, our answer is B.

3 0
3 years ago
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MAVERICK [17]

Answer:

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Step-by-step explanation:

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Multiply by -6

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6 0
3 years ago
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lutik1710 [3]

Answer:

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Multiply 6 times 7 = 42.

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