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nata0808 [166]
3 years ago
11

Student is training 4 a track team during the first 3 months of the year by running 30 minutes every day, while averaging 5 mile

s each day.
Select graph that correctly shows the total miles ran during the time of training program​

Mathematics
1 answer:
Novay_Z [31]3 years ago
4 0

30 minutes  -  5 miles;

1 hour -  10 miles

10 hours - 100 miles ...

The independent value is plotted along the x- axis ( Hours ) and the dependent variable is plotted  along the y-axis ( Miles ). Also:

3 months = 90 days

90 x 1/2 hours = 45 hours

Answer: The graph B ) ( or the second one ).  

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If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
2 years ago
Hi, can somoene please check why my solution and explain why I get the wrong answer.
trapecia [35]

Answer:

a_n=(1-n)2^n+3^n

Step-by-step explanation:

You are correct down to the part where you add the partial results:

a_n=a_n^h+a_n^p=A3^n+B2^n-n2^n\\\text{Using the given starter values, we can find A, B:}\\a_0=2=A\\a_1=7=3A+2B+2\\\text{has solution A=1, B=1, so ...}\\\\a_n=3^n+2^n-n2^n

4 0
3 years ago
A student in Greece discovers a pottery bowl that contains 65% of its original amount of C-14
stira [4]

There isn't enough information to answer

4 0
3 years ago
X + 4 5/6 = 9 <br> x + 3 5/6 = 8<br><br> What is x? <br><br> x has to be the same in each equation
topjm [15]

Answer:

x= 25/6 it is the same in both equations

7 0
3 years ago
Let ABCDEFGH be a cube and M the midpoint of GH. It is known that the distance between the lines BM and AD is a<img src="https:/
vovikov84 [41]

Answer:

√5

Step-by-step explanation:

We suppose the vertices are named clockwise around the top of the cube, then clockwise around the bottom (looking down from above the cube), with vertex E below vertex D. Then line AD is in plane ADEF, and line BM is in plane BCHG.

The distance between the named parallel planes is the distance between the lines. That distance is AB, which is given as √5.

_____

A diagram helps.

8 0
3 years ago
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